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Elina [12.6K]
3 years ago
12

Asap I need help plz no files

Mathematics
1 answer:
Ivanshal [37]3 years ago
8 0

Answer:

12.8

Step-by-step explanation:

Find scale factor

   10/2.5 = 4

   12.5/2.5 = 5

   4:5

Use scale factor to find x

   16 * 4/5 = 12.8

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SOLVE THE EQUATION<br> −9(x + 6) + 60 = 13 − 10x
yuradex [85]

Answer:

x=7

Step-by-step explanation:

−9(x + 6) + 60 = 13 − 10x

Distribute

−9x -54 + 60 = 13 − 10x

Combine like terms

-9x +6 = 13 -10x

Add 10x to each side

-9x+10x +6 = 13-10x+10x

x +6 = 13

Subtract 6 from each side

x+6-6=13-6

x = 7

7 0
3 years ago
What is the location of the point on the number line that is 3/7 of the way from A=6 to B=20?
-Dominant- [34]

Answer:

12

Step-by-step explanation:

20-6=14 (Distance between points) then 14*3/7=6.

3/7 of the distance from A=6 to B=20 is 6. Thus, we find the point that is

3/7 of the distance from A=6 to B=20 by adding 6 to 6.

6+6= 12

Therefore, the point that is

3/7 from A=6 to B=20 is 12.

7 0
2 years ago
Write two equivalent fractions for the point on the number line.
navik [9.2K]

The values on the number line are between 0 and 1. There are 8 points from 0. The distance between two consecutive points would be

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Since the given point is on the second point after 0, the equivalent value would be

2 * 1/8 = 2/8

Dividing the numerator and denominator of 2/8 by 2, we have 1/4

Thus, the two equivalent fractions for the point on number line are

2/8 and 1/4

5 0
1 year ago
To draw a line segment perpendicular to XY passing through point x
Andrew [12]
What does perpendicular mean? Well, in elementary geometry it mean 2 lines that intersect at a right angle. (90°).

So for Part one. all you need to do is draw a straight line down from the point X. Name the end point of that line M. 

Now you will connect the line M and Z.

Thats it! I hope this helped!! :)




3 0
3 years ago
Read 2 more answers
Not sure what this question is asking...
zalisa [80]
3)

\bf ~~~~~~~~~~~~\textit{negative exponents}\\\\&#10;a^{-n} \implies \cfrac{1}{a^n}&#10;\qquad \qquad&#10;\cfrac{1}{a^n}\implies a^{-n}&#10;\qquad \qquad &#10;a^n\implies \cfrac{1}{a^{-n}}&#10;\\\\&#10;-------------------------------\\\\&#10;\cfrac{-9}{2x^5}\implies \cfrac{-3^2}{2x^5}\implies \cfrac{-3^2}{1}\cdot \cfrac{1}{2}\cdot \cfrac{1}{x^5}\implies -\cfrac{1}{3^{-2}}\cdot 2^{-1}\cdot x^{-5}&#10;\\\\\\&#10;-\cfrac{2^{-1}x^{-5}}{3^{-2}}



4)

\bf 5^{-2}+5^0\implies \cfrac{1}{5^2}+1\implies \cfrac{1}{25}+1\implies \cfrac{1+25}{25}\implies \cfrac{26}{25}
6 0
3 years ago
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