Answer:
The system of equation can be used for determine the number of small and the large dogs groomed are
x + y = 22
43x + 75y = 1234
Step-by-step explanation:
Let us assume that the number of small dogs groomed be x.
Let us assume that the number of lagre dogs groomed be y.
As given
Paws at play made a total of $1,234 grooming 22 dogs.
Than the equation becomes
x + y = 22
Paws at play charges $43 to groom each small dog and $75 for each large dog.
Than the equation becomes
43x + 75y = 1234
Therefore the system of equation can be used for determine the number of small and the large dogs groomed are
x + y = 22
43x + 75y = 1234
Answer:
There is a total of 45 members in the math club.
Step-by-step explanation:
What I did is I multiplied 9 by 5 and got 45. I multiplied 9 by 5 because the question stated that 9 students are 20%. 20% times 5 would be 100%, which would be the total number of students.
Hope this helped :)
Answer: Choice C
The first inequality is 
The second inequality is 
Replace x with whatever letter your teacher is using
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Let x be the number of cans collected on week 3
Add this to the previous totals (for weeks 1 and 2) to get 124 + 121 + x. I'm going to leave this as is and not simplify. This is so the answer matches up. This total must be greater than or equal to 400, meaning 124+121+x can be 400 or larger.
124+121+x >= 400
245+x >= 400 .... combine like terms
x >= 400-245 .... subtract 245 from both sides
x >= 155
So you need to collect at least 155 cans for the third week so that you'll have at least 400 cans total.
