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2 years ago

These two Scalene triangles are similar with a scale of 5:2. What is true about these figures?

Mathematics

2 answers:

Alika [10]2 years ago

5 0

Answer:

top right one ac/df= 5/2

Step-by-step explanation:

i got it right on im

Ostrovityanka [42]2 years ago

4 0

Answer:AC/DF =5/2

Step-by-step explanation: since triangle ABC and triangle DEF have a scale of 5/2 the side from the bigger triangle (ABC) would be 5 and the smaller triangle (DEF) would be 2.

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How to calculate the three averages for the given data?

vichka [17]

Answer:

Add the numbers together and divide by the number of numbers. (The sum of values divided by the number of values). Arrange the numbers in order, find the middle number. (The middle value when the values are ranked).

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2 years ago

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3 years ago

Read 2 more answers

Consider the quadratic equation ax^2+bx+5=0,where a, b and c are rational numbers and the quadratic has two distinct zeros.

FrozenT [24]

You have shared the situation (problem), except for the directions: What are you supposed to do here? I can only make a educated guesses. See below:

Note that if ax^2+bx+5=0 then it appears that c = 5 (a rational number).

Note that for simplicity's sake, we need to assume that the "two distinct zeros" are real numbers, not imaginary or complex numbers. If this is the case, then the discriminant, b^2 - 4(a)(c), must be positive. Since c = 5,

b^2 - 4(a)(5) > 0, or b^2 - 20a > 0.

Note that if the quadratic has two distinct zeros, which we'll call "d" and "e," then

(x-d) and (x-e) are factors of ax^2 + bx + 5 = 0, and that because of this fact,

- b plus sqrt( b^2 - 20a )
d = ------------------------------------
2a

and

 - b minus sqrt( b^2 - 20a )
e = ------------------------------------
2a

Some (or perhaps all) of these facts may help us find the values of "a" and "b." Before going into that, however, I'm asking you to share the rest of the problem statement. What, specificallyi, were you asked to do here?

7 0

3 years ago

Describe the number 78 in two different ways

statuscvo [17]

It is a high number and in the tens pop ace is 70

3 0

3 years ago

2. In a school of 320 students, 85 students are in the band, 200 students are on sports teams, and 60 students

Alja [10]

Answer:

60 students are involved in either band or sports.

95 students are not involved in either sports or band.

Step-by-step explanation:

Given:

In a school of 320 students, 85 students are in the band, 200 students are on sports teams, and 60 students participate in both activities.

Now, to find the students are involved in either sports or band. And students who are not involved in either sports or band.

Total number of students = 320.

Number of students in the band = 85.

Number of students in the sports team = 200.

Number of students participate in both activities = 60.

Thus, 60 students are involved in either band or sports.

So, the number of students in the band adding number of students in the sports team we get:

200 + 85 = 285.

Then, to subtract the number of students participate in both activities we get:

285 - 60 = 225.

Thus, the remaining students are = 225.

Now, to get the students who are not involved in either sports or band we subtract the total number of students from the remaining students:

$320-225$

$=95.$

Therefore, 60 students are not involved in either band or sports. 95 students are not involved in either sports or band.

8 0

2 years ago