The mass of oxygen required is 17.06 g; the mass of carbon dioxide produced is 300 g; the mass of copper (ii) nitrate produced is 16.7 g.
<h3>What is the equation of the synthesis of water from hydrogen and oxygen?</h3>
The equation of the synthesis of water from hydrogen and oxygen is given as follows:
The grams of oxygen required is given below:
![19.2 g\:of H_{2} \times\frac{1\:mol H_{2}}{18 g\:H_{2}} \times\frac{1mol\:O_{2}}{2 mol\:H_{2}}\times\frac{32g\:O_{2}}{1 mol\:O_{2}} = 17.06 g\: O_{2}](https://tex.z-dn.net/?f=19.2%20g%5C%3Aof%20H_%7B2%7D%20%5Ctimes%5Cfrac%7B1%5C%3Amol%20H_%7B2%7D%7D%7B18%20g%5C%3AH_%7B2%7D%7D%20%5Ctimes%5Cfrac%7B1mol%5C%3AO_%7B2%7D%7D%7B2%20mol%5C%3AH_%7B2%7D%7D%5Ctimes%5Cfrac%7B32g%5C%3AO_%7B2%7D%7D%7B1%20mol%5C%3AO_%7B2%7D%7D%20%3D%2017.06%20g%5C%3A%20O_%7B2%7D)
The equation of the combustion of propane is given as follows:
![C_{3}H_{8} + 5\:O_{2}\rightarrow3\:CO_{2}+4\:H_{2}O](https://tex.z-dn.net/?f=C_%7B3%7DH_%7B8%7D%20%2B%205%5C%3AO_%7B2%7D%5Crightarrow3%5C%3ACO_%7B2%7D%2B4%5C%3AH_%7B2%7DO)
The mass of carbon dioxide produced is given below:
![100 g\:of\:C_{3}H_{8} \times\frac{1\:mol\:C_{3}H_{8}}{44 g\:C_{3}H_{8}} \times\frac{3\:mol\:CO_{2}}{1\:mol\:C_{3}H_{8}}\times\frac{44g\:CO_{2}}{1 mol\:CO_{2}} = 300 g\:CO_{2}](https://tex.z-dn.net/?f=100%20g%5C%3Aof%5C%3AC_%7B3%7DH_%7B8%7D%20%5Ctimes%5Cfrac%7B1%5C%3Amol%5C%3AC_%7B3%7DH_%7B8%7D%7D%7B44%20g%5C%3AC_%7B3%7DH_%7B8%7D%7D%20%5Ctimes%5Cfrac%7B3%5C%3Amol%5C%3ACO_%7B2%7D%7D%7B1%5C%3Amol%5C%3AC_%7B3%7DH_%7B8%7D%7D%5Ctimes%5Cfrac%7B44g%5C%3ACO_%7B2%7D%7D%7B1%20mol%5C%3ACO_%7B2%7D%7D%20%3D%20300%20g%5C%3ACO_%7B2%7D)
The equation of the reaction of copper and silver nitrate is given as follows:
![Cu + 2\:AgNO_{3}\rightarrow Cu(NO_{3})_{2} + 2\:Ag](https://tex.z-dn.net/?f=Cu%20%2B%20%202%5C%3AAgNO_%7B3%7D%5Crightarrow%20Cu%28NO_%7B3%7D%29_%7B2%7D%20%2B%202%5C%3AAg)
![5.7 g\:Cu \times\frac{1\:mol\:Cu}{64 g\:Cu} \times\frac{1mol\:Cu(NO_{3})_{2}}{1mol\:Cu}\times\frac{188g\:Cu(NO_{3})_{2}}{1 mol\:Cu(NO_{3})_{2}} = 16.7 g\:Cu(NO_{3})_{2}](https://tex.z-dn.net/?f=5.7%20g%5C%3ACu%20%5Ctimes%5Cfrac%7B1%5C%3Amol%5C%3ACu%7D%7B64%20g%5C%3ACu%7D%20%5Ctimes%5Cfrac%7B1mol%5C%3ACu%28NO_%7B3%7D%29_%7B2%7D%7D%7B1mol%5C%3ACu%7D%5Ctimes%5Cfrac%7B188g%5C%3ACu%28NO_%7B3%7D%29_%7B2%7D%7D%7B1%20mol%5C%3ACu%28NO_%7B3%7D%29_%7B2%7D%7D%20%3D%2016.7%20g%5C%3ACu%28NO_%7B3%7D%29_%7B2%7D)
Therefore, the mass of oxygen required is 17.06 g; the mass of carbon dioxide produced is 300 g; the mass of copper (ii) nitrate produced is 16.7 g.
Learn more about mass and mole ratio at: brainly.com/question/16806688
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"Iron and sulfur are both elements from the periodic table of elements. As such, each one has its own unique set of physical and chemical properties. Iron is a metal, while sulfur is a nonmetal. When these two are heated together, the iron atoms combine with the sulfur atoms to make a compound known as iron sulphide. A compound is different from elements in that it is made from the chemical union of two or more elements. Iron sulphide is not iron or sulfur; it is a pure substance with its own set of distinguishing physical and chemical characteristics. A mixture, on the other hand, is what you get by combining two or more elements, but not chemically combining them. In the case of the iron and the sulfur, if you mix them and provide no heat, you simply have a mixture of iron and sulfur. Mixtures are different from compounds in that they are easily separated. A magnet could be used to separate the iron from the sulfur, because iron is attracted to magnets, while sulfur is not." https://www.enotes.com/homework-help/explain-why-iron-sulphide-compound-not-just-336735 - I hope this helps! :)
Answer:
Explanation:
Examples of extended structures could include sodium chloride or diamonds. Examples of molecular-level models could include drawings, 3D ball and stick structures, or computer representations showing different molecules with different types of atoms.]
The answer is B) heat will flow from the water to the copper until they both reach the same temperature