the directions in the candy recipe for pralines instruct the cook to remove the pot containing the candy mixture from the heat w
1 answer:
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Answer:
New volume is 25.0 mL
Explanation:
Let's assume the gas sample behaves ideally.
According to combined gas law for an ideal gas-
where, and
represent initial and final pressure respectively
and
represent initial and final volume respectively
and
represent initial and final temperature (in kelvin) respectively
Here, ,
,
and
So,
So, the new volume is 25.0 mL
Answer:
Volume of the gas at 44°C is <u>258 ml.</u>
Explanation
here,
using Charles' law ,
where , V= initial volume v= final volume
T=initial temperature t = final temperature
Given - pressure is constant ,
so , putting the values -
V= 240ml
T= 22 + 273K = 295K (since converting celsius into kelvin that
is +273K )
v =?
t = 44+ 273K = 317K
Now , putting the given values in charles' law ,
240ml x317K = v x 295K (through cross multiplication )
v =
= 258ml .
thus ,<u> the volume of carbon dioxide in a container at 44°C IS 258ml .</u>
Answer: There will be 131.3 tons of that will be generated.
Explanation : We have the data as 72 tons of ,
is 101 tons and
as 38 tons.
Conversion of 1 ton to kg will be approximately 907.2 Kg
We have to convert the given data of tons into kg for all;
So, moles of = (72 tons X 907.2 Kg/ton X 1000 g/Kg) / (34.082 g/ mol) = 1.916 X
moles
Now, moles of = (101 tons X 907.2 Kg/ton X 1000 g/Kg) / (32 g/mol) = 2.80 X
moles
And, = (38 tons X 907.2 Kg/ton X 1000 g/Kg) / (18.016 g/mol)
= 1.03 X moles
Now, we have to calculate the moles of
so, 1.916 X moles / 2 moles of
= 958 X
Now, for ;
So, 2.80 X moles / 3 moles of
= 933.3 X
moles
Here, we can see that is acting as a limiting reactant.
Now, moles of = 2.80 X
X (2 moles of
/ 3 moles of
) = 1.86 X
Now converting this into mass,
Mass = Moles X Molar Mass
Mass = 1.86 X X (64.066 g/mol X
kg/g) X (1 ton / 907.2 Kg)
= 131.3 tons of