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nikklg [1K]
3 years ago
15

the directions in the candy recipe for pralines instruct the cook to remove the pot containing the candy mixture from the heat w

hen the candy micture reaches the soft-ball stage. the soft ball stage corresponds to the temperature of 236°F. after the soft ball stage is reached ,the pecans and vanilla are added. can a celsius thermometer with a range of -10°C be used to determine when the soft ball stage is reached in the candy micture? why or why not?
Chemistry
1 answer:
Oksanka [162]3 years ago
3 0

A Celsius thermometer with a range of -10°C cannot be used to determine when the soft ball stage is reached in the candy mixture.  

Temperature is most commonly measured with a thermometer that has two different scales: Fahrenheit and Celsius. Water freezes at 0°C and boils at 100°C on the Celsius scale and freezes at 32°F and boils at 212°F on the Fahrenheit scale.

Temperature of 236°F corresponds to 113.3°C. Now a Celsius scale has a maximum of 100°C on the thermometer. Hence a Celsius thermometer cannot be used to measure a temperature that corresponds to 236°F.  


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1. Molarity of a a solution = number of moles of solute/ volume of solution in L

Number of moles of solute = mass of solute/molar mass of solute

Molar mass of NaC₂H₃O₂ = 82 g/mol, mass of NaC₂H₃O₂ = 245 g

Number of moles of NaC₂H₃O₂ = 245 g / 82 g/mol = 2.988 moles

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2. Percentage by mass of a substance = mass of substance /mass of solution × 100%

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Mass of water = 1000 g/L × 2.65 L = 2650 g

Mass of solution = mass of water + mass of solute = 245 + 2650 =2895 g

Percentage by mass of NaC₂H₃O₂ = 245/2895 × 100% = 8.46%

3. Mole fraction of NaC₂H₃O₂ = moles of NaC₂H₃O₂/moles of solution

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Moles of water = 2650 g / 18 g/mol = 147.222 moles

Moles of solution = moles of solute + moles of water = 147.222 + 2.988 = 150.21

Moles of NaC₂H₃O₂ =2.988 moles

Moles fraction of NaC₂H₃O₂ =2.988/150.21 = 0.0199

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