Answer:
O Charles's law
.
Explanation:
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In this case, since the use of gas laws leads to a good comprehension of how gases behave towards volume, pressure and temperature, we can review that the Boyle's law explains the pressure-volume variation, the Dalton's law the partial pressure effect, the Gay-Lussac's law that of pressure and temperature and the Charles' that of temperature and volume at constant pressure; thus, the answer for the asked question is:
O Charles's law
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<span>b.mixtures are made up of more than one component</span>
Answer:
for instance :
water , H²O , and hydrogen peroxide . H²O² , are alike
in that their respective molecules are composed of hydrogen and oxygen atomd . hope its helpful . Good luck :)
The molecule that could diffuse across the plasma membrane is methane (CH4).
<h3>What is diffusion?</h3>
Diffusion is the movement of fluids or substances from regions of high concentration toward regions of lower concentration.
The plasma membrane is the semipermeable membrane that surrounds the cytoplasm of a cell. The semipermeability means that it allows some molecules through but blocks other substances.
The semipermeable plasma membrane readily allows the passage of small hydrophobic and polar molecules.
Therefore, the molecule that could diffuse across the plasma membrane is methane (CH4).
Learn more about semipermeability at: brainly.com/question/1652796
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Answer:
A) Sample B has more calcium carbonate molecules
Explanation:
M = Molar mass of calcium carbonate = 100.0869 g/mol
= Avogadro's number = 
For the 4.12 g sample
Moles of a substance is given by

Number of molecules is given by

For the 19.37 g sample

Number of molecules is given by


So, sample B has more calcium carbonate molecules.
The ratio of the elements of carbon, oxygen, calcium atoms, ions, has to be same in both the samples otherwise the samples cannot be considered as calcium carbonate. Same is applicable for impurities. If there are impurites then the sample cannot be considered as calcium carbonate.