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3 years ago

Heather drove a constant rate

Mathematics

2 answers:

mrs_skeptik [129]3 years ago

3 0

Answer:

cool

Step-by-step explanation:

bazaltina [42]3 years ago

3 0

Answer:

What?, haha... can you finish the sentence, or put a picture, cause i'm not understanding this

Step-by-step explanation:

confusion 101

You might be interested in

Use square ABCD for this problem<br><br> IF AC=26,find BC.

katen-ka-za [31]

Answer:

x= $\sqrt{338}$

Step-by-step explanation:

$a^2+b^2=c^2$

$x^2+x^2=$ $26^2$

$2x^2=26^2$

$2x^2=676$

/2 /2

$x^2=338$

$\sqrt{x^2} =\sqrt{338}$

x= $\sqrt{338}$

8 0

3 years ago

Read 2 more answers

There are many toys in a kindergarten. The ratio of the number of dolls to the number of balls to the number of cars is 7:8:5. I

Nina [5.8K]

Answer:

There are 28 dolls, 32 balls, 20 cars for 80 total toys

Step-by-step explanation:

dolls : balls: cars: total

7 8 5 (7+8+5)

7 8 5 20

We have a total of 80

80/20 = 4

We need to multiply each number by 4

dolls : balls: cars: total

7*4 8*4 5*4 20*4

28 32 20 80

There are 28 dolls, 32 balls, 20 cars for 80 total toys

4 0

3 years ago

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S.

sweet-ann [11.9K]

Answer:

2.794

Step-by-step explanation:

Recall that if G(x,y) is a parametrization of the surface S and F and G are smooth enough then

$\bf \displaystyle\iint_{S}FdS=\displaystyle\iint_{R}F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})dxdy$

F can be written as

F(x,y,z) = (xy, yz, zx)

and S has a straightforward parametrization as

$\bf G(x,y) = (x, y, 3-x^2-y^2)$

with 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\frac{\partial G}{\partial x}= (1,0,-2x)\\\\\displaystyle\frac{\partial G}{\partial y}= (0,1,-2y)\\\\\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y}=(2x,2y,1)$

we also have

$\bf F(G(x,y))=F(x, y, 3-x^2-y^2)=(xy,y(3-x^2-y^2),x(3-x^2-y^2))=\\\\=(xy,3y-x^2y-y^3,3x-x^3-xy^2)$

and so

$\bf F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})=(xy,3y-x^2y-y^3,3x-x^3-xy^2)\cdot(2x,2y,1)=\\\\=2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2$

we just have then to compute a double integral of a polynomial on the unit square 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\int_{0}^{1}\displaystyle\int_{0}^{1}(2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2)dxdy=\\\\=2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}ydy+6\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^4dy+\\\\+3\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}x^3dx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}y^2dy$

=1/3+2-2/9-2/5+3/2-1/4-1/6 = 2.794

5 0

2 years ago

Which statement is true regarding the graphed functions ?

daser333 [38]

will u give me diamond dedo please let

Step-by-step explanation:

opbolte99 I am very sorry for what is ur id number on it n

8 0

2 years ago

An angle measures 166° more than the measure of a supplementary angle. What is the measure of each angle?

expeople1 [14]

Supplementary means they add up to 180

angle 1 = x
angle 2 = x + 166

so x + x + 166 = 180
2x = 14
x = 7

so angle 1 = 7 angle 2 = x + 166 = 173

5 0

3 years ago