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maw [93]
3 years ago
6

Heather drove a constant rate

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
3 0

Answer:

cool

Step-by-step explanation:

bazaltina [42]3 years ago
3 0

Answer:

What?, haha... can you finish the sentence, or put a picture, cause i'm not understanding this

Step-by-step explanation:

confusion 101

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A candy store owner wants to mix some candy costing $1.25 a pound
maria [59]

The candy store owner should use 37.5 pounds of the candy costing $1.25 a pound.

Given:

  • Candy costing $1.25 a pound is to be mixed with candy costing $1.45 a pound
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To find: The amount of candy costing $1.25 a pound that should be mixed

Let us assume that the resulting mixture should be made by mixing 'x' pounds of candy costing $1.25 a pound.

Since the total weight of the resulting mixture should be 50 pounds, 'x' pounds of candy costing $1.25 a pound should be mixed with '50-x' pounds of candy costing $1.45 a pound.

Then, the resulting mixture contains 'x' pounds of candy costing $1.25 a pound and '50-x' pounds of candy costing $1.45 a pound.

Accordingly, the total cost of the resulting mixture is 1.25x+1.45(50-x)

However, the resulting mixture should be 50 pounds and should cost $1.30 a pound. Accordingly, the total cost of the resulting mixture is 1.30 \times 50

Equating the total cost of the resulting mixture obtained in two ways, we get,

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x=\frac{7.5}{0.2}

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This implies that the resulting mixture should be made by mixing 37.5 pounds of candy costing $1.25 a pound.

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