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irina1246 [14]
3 years ago
10

Marisol is given the following three lengths of a possible triangle: 1, 2 and 7. Would these side lengths form a triangle?

Mathematics
1 answer:
Leno4ka [110]3 years ago
6 0

Answer:

no because 1+2<7. To form a triangle any two lengths have to be greater than third one

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I need help with this
Finger [1]

ask your teacher.

use a calculator.

Use math tutoring for this module.

Pay more attention to the lecture.

3 0
3 years ago
Please help!<br><br> 7|-7x-3|=21
arlik [135]

Divide by 7.

... |-7x -3| = 3

Unfold to two equations.

... -3 = -7x -3 . . . . . the content of the absolute value is negative

... 0 = -7x . . . . . . . . add 3

... 0 = x . . . . . . . . . . divide by -7

and

... 3 = -7x -3 . . . . . . the content of the absolute value is positive

... 6 = -7x . . . . . . . . add 3

... -6/7 = x . . . . . . . . divide by -7

The solutions are ...

... x = -6/7 or x = 0

_____

Many graphing programs will happily tell you the locations of x- and y-intercepts, so it is convenient to rewrite the equation so its value is zero at the solution points. We can do that by subtracting the right side constant to get ...

... 7|-7x -3| -21 = 0

7 0
3 years ago
(43 points) In the US, 85% of the population has Rh positive blood. Suppose we take a random sample of 6 persons and let Y denot
VladimirAG [237]

Answer:

a) Binomial distribution with parameters p=0.85 q=0.15 n=6

b) 62.29%

c) 2.38%

d) See explanation below

Step-by-step explanation:

a)

We could model this situation with a binomial distribution

P(6;k)=\binom{6}{k}p^kq^{6-k}

where P(6;k) is the probability of finding exactly k people out of 6 with Rh positive, p is the probability of finding one person with Rh positive and q=(1-p) the probability of finding a person with no Rh.

So

\bf P(Y=k)=\binom{6}{k}(0.85)^k(0.15)^{6-k}

b)  

The probability that Y is less than 6 is

P(Y=0)+P(Y=1)+...+P(Y=5)

Let's compute each of these terms

P(Y=0)=P(6;0)=\binom{6}{0}(0.85)^0(0.15)^{6}=1.139*10^{-5}

P(Y=1)=P(6;1)=\binom{6}{1}(0.85)^1(0.15)^{5}=0.0000387281

P(Y=2)=P(6;2)=\binom{6}{2}(0.85)^2(0.15)^{4}=0.005486484

P(Y=3)=P(6;3)=\binom{6}{3}(0.85)^3(0.15)^{3}=0.041453438

P(Y=4)=P(6;4)=\binom{6}{4}(0.85)^4(0.15)^{2}=0.176177109

P(Y=5)=P(6;5)=\binom{6}{5}(0.85)^5(0.15)^{1}=0.399334781

and adding up these values we have that the probability that Y is less than 6 is

\sum_{i=1}^{5}P(Y=i)=0.622850484\approx 0.6229=62.29\%

c)

In this case is a binomial distribution with n=200 instead of 6.

p and q remain the same.

The mean of this sample would be 85% of 200 = 170.  

In a binomial distribution, the standard deviation is  

s = \sqrt{npq}

In this case  

\sqrt{200(0.85)(0.15)}=5.05

<em>Let's approximate the distribution with a normal distribution with mean 170 and standard deviation 5.05</em>

So, the approximate probability that there are fewer than 160 persons with Rh positive blood in a sample of 200 would be the area under the normal curve to the left of 160

(see picture attached)

We can compute that area with a computer and find it is  

0.0238 or 2.38%

d)<em> In order to approximate a binomial distribution with a normal distribution we need a large sample like the one taken in c).</em>

In general, we can do this if the sample of size n the following inequalities hold:

np\geq 5 \;and\;nq \geq 5

in our case np = 200*0.85 = 170 and nq = 200*0.15 = 30

4 0
3 years ago
What is the quotient of 5 divided by 1/3
Pachacha [2.7K]

Answer:

15

Step-by-step explanation:

5 divided by 1/3 is the same as if you flip the denominator meaning 5 x 3 which is 15

4 0
3 years ago
Read 2 more answers
Seven-ninths of the pencils in a box are yellow. Three-tenths of the yellow pencils are sharpened. What fraction represents the
jek_recluse [69]

Answer:

7/30

Step-by-step explanation:

We are given that Seven-ninths (7/9) of the pencils in a box are yellow and three-tenths (3/10) of the yellow pencils are sharpened.

To find the fraction that represents sharpened yellow pencils, we find the product of the the fraction of yellow pencils and the fraction of yellow pencils that are sharpened.

That is:

=> (7 / 9) * (3 / 10)

=(7 * 3) / (9 * 10)

= 21 / 90

= 7 / 30

7/30 represents the fraction of sharpened yellow pencils.

3 0
3 years ago
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