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Yuri [45]
2 years ago
11

Sarah has gone to work for the past 60 days. On 39 of those days she arrived at work before 8 AM. On the rest of those days she

arrived after 8:30 AM. What is the experimental probability that she will arrive at 8 AM on the next day she goes to work.
Mathematics
1 answer:
puteri [66]2 years ago
4 0

Answer:

13/20

Step-by-step explanation:

Probability is the ratio of the number of possible outcome to the number of total outcome.

Given that for the past 60 days, on 39 of those days she arrived at work before 8 AM while for the rest of those days she arrived after 8:30 AM, the probability that she will arrive at 8 AM on the next day she goes to work

= 39/60

= 13/20

In decimal, this will be expressed as 0.65 and 65% in percentage.

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Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

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\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

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There are lots of ways to compute this. What I did was to consider the complex contour integral

\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz

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\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}

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The simplified expression of 32/5 x 3(-7/5) is  -672/25

<h3>How to simplify the expression?</h3>

The mathematical expression is given as:

32/5 x 3(-7/5)

Evaluate the product of 3 and -7/5

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Evaluate the product of 32 and -21

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Read more about expressions at:

brainly.com/question/723406

#SPJ1

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