The given function : h(x) = 6 - x
We know that for any functions f(x) and g(x)
f*g (x)=f(x)\times g(x)
Therefore , h*h (x)=h(x)\times h(x)
h*h (x)=(6-x)(6-x)=(6-x)^2
h*h (x)=(6)^2-2(6)(x)+x^2 [ Using identity (a-b)^2=a^2+2ab+b^2 ]
h*h (x)=36-12(x)+x^2
\-------->\ h*h (x)=36-12(x)+x^2 Now, at x= 10 , we get
h*h (10)=36-12(10)+(10)^2
h*h (10)=36-120+100=36+100-120=136-120=16
Hence, the value of (h*h)(10) = 16
hoped it helped
Answer:
t = 8.017 or 0.608 (nearest hundredth)
Step-by-step explanation:
when h = 78:
Using quadratic formula:
Answer:
Step-by-step explanation:
A) 604.2
B) 609.9
C) 537.42
D) 542.49
Answer:
(0, 6)
(1, 
)
(2, 7)
Step-by-step explanation:
Just implement x and solve for y.
Common Pythagorean triples include
(3, 4, 5)
(5, 12, 13)
(7, 24, 25)
(9, 40, 41)
The only Pythagorean triple that is an arithmetic sequence is (3, 4, 5), so any arithmetic sequence that is a Pythagorean triple must be a multiple of that, such as (9, 12, 15) or (15, 20, 25).
The arithmetic sequences of selections B and D are unrelated to the (3, 4, 5) triple, so cannot be Pythagorean triples. For selection A, we know that 9² + 11² = 81 + 121 = 202 > 14², so that is not a right triangle.
The appropriate selection is ...
C. 7, 24, 25
