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Fynjy0 [20]
3 years ago
14

I need to know the explanation on how to find the answer to #21. On the text book answer key it states that the answer is ons ca

rrier takes 1 Hour while the other carrier takes 2 Hours. This is an algebra question.

Mathematics
1 answer:
Naya [18.7K]3 years ago
8 0

Answer:

2 hours and 3 hours

Step-by-step explanation:

First, convert the time from hours and minutes to just hours.

1 hr and 12 min = 1.2 hr

Let's say t is the time it takes for one mail carrier, and t+1 is the time for the other mail carrier.

The speed of the first mail carrier is 1 route / t hours.

The speed of the second mail carrier is 1 route / (t+1) hours.

Their combined speed is:

1 route / 1.2 hours = 1 route / t hours + 1 route / (t+1) hours

Solving this equation:

1 / 1.2 = 1 / t + 1 / (t + 1)

5 / 6 = 1 / t + 1 / (t + 1)

Multiply both sides by 6t (t + 1):

5t (t + 1) = 6 (t + 1) + 6t

5t² + 5t = 6t + 6 + 6t

5t² + 5t = 12t + 6

5t² − 7t − 6 = 0

Factor:

(t − 2) (5t + 3) = 0

t = 2 or -0.6

Since t must be positive, t = 2, so t+1 = 3.

It takes each carrier 2 hours and 3 hours working alone.

The answer key must have a mistake.  If one of the carriers can deliver mail in 1 hour, then it would take less than 1 hour working together.

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Answer:

x=1

Step-by-step explanation:

5 − 3 x = x + 1

 Move all terms containing  x  to the left side of the equation.

5 − 4 x = 1

Move all terms not containing  x  to the right side of the equation. − 4 x = − 4

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3 0
3 years ago
For what value of x does 3 Superscript 2 x Baseline = 9 Superscript 3 x minus 4?
Natalka [10]
Answer: B
Hope this helps
8 0
3 years ago
Read 2 more answers
Find the area of the triangle ABC with the coordinates of A(10, 15) B(15, 15) C(30, 9).
lions [1.4K]

Check the picture below.  so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}

(\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill

\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}

6 0
2 years ago
Solve the equation. If there is no solution, write no solution. –2 |h – 7| = –28
Elodia [21]
The answer is, A) No solution
8 0
3 years ago
a tank is 3/7 full of water.After removing 420 litres it became 12/35 full .how much can the tank hold when full? ​
insens350 [35]

Answer:

4900 Litres

Step-by-step explanation:

First we need a common demoninator:

3/7=15/35

Then we subtract the two to figure out how much 420 Litres is:

15/35-12/35=3/35

3/35=420 litres

Divide amount by the numerater for thow much 1/x is.

1/35=140

and multiply by the denomenator to get a full number on your fraction, and therefore a full tank.

140 x 35 = 4900

5 0
1 year ago
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