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Deffense [45]
3 years ago
9

The larger root of the equation (x+4)(x+3)=0 is and why???

Mathematics
2 answers:
sladkih [1.3K]3 years ago
7 0
(x+4)(x+3)=0 \\&#10;x+4=0 \ \lor \ x+3=0 \\&#10;x=-4 \ \lor \ x=-3 \\ \\&#10;-4 < -3 \\ \\&#10;\hbox{the larger root} \Rightarrow \boxed{ -3}
Monica [59]3 years ago
6 0
Break the problem down into (x+4)=0 and (x+3)=0
X+4=0 so you subtract 4 from each side giving you x=-4
X+3=0 subtracting 3 from each side giving you x=-3
-3 is larger than -4 because when dealing with negative numbers, you want to be as close to one because that means the number is bigger.
Therefore -3 is the larger root
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Step-by-step explanation:

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3 years ago
A certain number of sixes and nines is added to give a sum of 126; if the number of sixes and nines is interchanged, the new sum
galina1969 [7]

Answer:

Original number of sixes = 6

Original number of nines = 10

Step-by-step explanation:

We are told in the question that:

A certain number of sixes and nines is added to give a sum of 126

Let us represent originally

the number of sixes = a

the number of nines = b

Hence:

6 × a + 9 × b = 126

6a + 9b = 126.....Equation 1

If the number of sixes and nines is interchanged, the new sum is 114.

For this second part, because it is interchanged,

Let us represent

the number of sixes = b

the number of nines = a

6 × b + 9 × a = 114

6b + 9a = 114.......Equation 2

9a + 6b = 114 .......Equation 2

6a + 9b = 126.....Equation 1

9a + 6b = 114 .......Equation 2

We solve using Elimination method

Multiply Equation 1 by the coefficient of a in Equation 2

Multiply Equation 2 by the coefficient of a in Equation 1

6a + 9b = 126.....Equation 1 × 9

9a + 6b = 114 .......Equation 2 × 6

54a + 81b = 1134 ........ Equation 3

54a + 36b = 684.........Equation 4

Subtract Equation 4 from Equation 3

= 45b = 450

divide both sides by b

45b/45 = 450/45

b = 10

Therefore, since the original the number of nines = b,

Original number of nines = 10

Also, to find the original number of sixes = a

We substitute 10 for b in Equation 1

6a + 9b = 126.....Equation 1

6a + 9 × 10 = 126

6a + 90 = 126

6a = 126 - 90

6a = 36

a = 36/6

a = 6

Therefore, the original number of sixes is 6

7 0
3 years ago
The quotient of two numbers is negative. It must be true that _____. a neither number is negative b one of the numbers is negati
vivado [14]
The answer is B.) one of the numbers is negative. 

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3 0
3 years ago
Read 2 more answers
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Dmitry [639]

Answer: 126.52

Step-by-step explanation:

The square root of 16,007 is approximately 126.52

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4 0
2 years ago
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