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yaroslaw [1]
3 years ago
5

The drawing plan for an art studio shows a rectangle that is 19.2 inches by 8

Mathematics
1 answer:
vazorg [7]3 years ago
4 0

Answer:

24 ft by 10 ft

240 ft

Step-by-step explanation:

19.2/4 = 4.8

4.8 · 5 = 24

8/4 = 2

2 · 5 = 10

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In choosing this year 327 voted musical and 115 voted drama. How many more students voted musical than drama
Lapatulllka [165]

Answer:

212 more student voted musical than drama .

Step-by-step explanation:

As given

In choosing this year 327 voted musical and 115 voted drama.

More students voted musical than drama = Total students voted for musical - Students voted for drama .

Putting values in the above

More students voted musical than drama = 327- 115

                                                                      = 212

Therefore 212 more student voted musical than drama .

5 0
3 years ago
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3 years ago
In a simple random sample of 300 boards from this shipment, 12 fall outside these specifications. Calculate the lower confidence
Lyrx [107]

Answer:

The 95% confidence interval for the percentage of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

Step-by-step explanation:

In a random sample of 300 boards the number of boards that fall outside the specification is 12.

Compute the sample proportion of boards that fall outside the specification in this sample as follows:

\hat p =\frac{12}{300}=0.04

The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The critical value of <em>z</em> for 95% confidence level is,

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a <em>z</em>-table.

Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.04\pm1.96\sqrt{\frac{0.04(1-0.04)}{300}}\\=0.04\pm0.022\\=(0.018, 0.062)\\\approx(1.8\%, 6.2\%)

Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

6 0
3 years ago
92. Calculate the mean of each data set below. Can you find any shortcuts that allow you to find the mean without having to do m
dimulka [17.4K]

Calculate the mean of each data set below. Can you find any shortcuts that allow you to find the mean without having to do much calculation? Homework help  6, 10, 6, 10 11, 12, 12, 13, 12 0, 5, 4, 8, 0, 7

Answer: To find the mean of the given observations. we just need to first find the sum of the given observations and the divide the calculate sum by the total number of observations.

So here:

Sum of of observations =6+ 10+ 6+10+11+12+12+13+12+0+ 5+ 4+ 8+ 0+7=116

Number of observations = 15

Therefore, the mean =\frac{116}{15}= 7.733

5 0
3 years ago
My car travels an average 12.3 km on each litre of petrol. What distance willI travel on 105 litres? *
Jobisdone [24]

Answer:

1291.5km

Step-by-step explanation:

12.3*105=1291.5km

3 0
3 years ago
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