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balu736 [363]
3 years ago
6

Find the number of real number solutions for the equation. x^2+5x+7=0

Mathematics
1 answer:
koban [17]3 years ago
7 0

Given a quadratic equation ax^2+bx+c=0, we define the discriminant as

\Delta = b^2-4ac

The number of real solutions of the equation depend on the sign of \Delta:

  • If \Delta>0 the equation has two solutions
  • If \Delta=0 the equation has one double solution
  • If \Delta the equation has no real solutions

In this case, we have

\Delta = 25-28=-3

And so this equation has no real solutions.

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Answer:

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Step-by-step explanation:

Fill in the given numbers and solve for T.

  I = PRT/100

  80 = 400·10·T/100

  80 = 40T . . . . . . . . . . . . simplify

  80/40 = T = 2 . . . . . . . . divide by the coefficient of T

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