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vovikov84 [41]
3 years ago
10

Need help with these. please show work​

Mathematics
1 answer:
koban [17]3 years ago
3 0

Answer:

baby momma aint shii she wont lemme see mai son

Step-by-step explanation:

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You are planning to hire a full-time electrician who will work 40 hours per week. If you plan on giving this new hire three week
tresset_1 [31]

Option b) 1960 is the total number of hours the electrician worked.

<u>Step-by-step explanation:</u>

It is given that, the full-time electrician will work 40 hours per week.

So, we need to know the total number of hours he could work in twelve months which is one year.

Therefore, one year has a total of 365 days.

<u>To find the number of weeks in twelve months :</u>

Number of weeks = Total days in one year / 7 days of week

⇒ 365 / 7

⇒ 52.14 (approximately 52 weeks)

The number of weeks in twelve months is 52 weeks.

Now, of this 52 weeks, the three weeks are given as vacation.

The total number of weeks the electrician worked = 52 weeks - 3 weeks

⇒ 49 weeks.

The electrician worked for 49 weeks.

To calculate the total number of hours he worked = 49 weeks × 40 hours

⇒ 1960 hours.

Therefore, the  total number of hours the electrician worked is 1960 hours which is option b).

5 0
3 years ago
7x-4y=-7 5x+y=22 please show work
Keith_Richards [23]
What exactly are you finding 

3 0
3 years ago
find the equation of a line that is parallel to the straight line 2x-y=-3 and crosses the x-axis at x=-5​
Alecsey [184]

Answer:

y=2x+10

Step-by-step explanation:

In line equations its helpful to write your line in the form y = ax + b. This helps because a is always the gadient of the line and b is always the y intercept.

In this case it is y=2x+3

All parallel lines have the same gradient. The gradient of this line = 2.

If the line crosses the x axis at x=-5, then when x =-5 y = 0.

If you put all this in the form y =ax + b you get 0 = 2(-5) +b

So all you need to do to find b is rearrange. b = 10.

Therefore your line has gradient 2 and y intercept 10.

y = 2x + 10

7 0
3 years ago
Why does a radical function with an even index only appear on one sode of the x-axis while a radical woth an odd index appears o
Vladimir79 [104]

Consider the equation y = x^2. No matter what x happens to be, the result y will never be negative even if x is negative. Example: x = -3 leads to y = x^2 = (-3)^2 = 9 which is positive.

Since y is never negative, this means the inverse x = sqrt(y) has the right hand side never be negative. The entire curve of sqrt(x) is above the x axis except for the x intercept of course. Put another way, we cannot plug in a negative input into the square root function for this reason. This similar idea applies to any even index such as fourth roots or sixth roots.

Meanwhile, odd roots such as a cube root has its range extend from negative infinity to positive infinity. Why? Because y = x^3 can have a negative output. Going back to x = -3 we get y = x^3 = (-3)^3 = -27. So we can plug a negative value into the cube root to get some negative output. We can get any output we want, negative or positive. So the range of any radical with an odd index is effectively the set of all real numbers. Visually this produces graphs that have parts on both sides of the x axis.

3 0
3 years ago
Please help me on 7EE thanks:)
Grace [21]
The answer is y=35+1.25x
8 0
3 years ago
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