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Gelneren [198K]
3 years ago
8

Please help and if ur helpful enough there’s like a bunch of questions I need answered on my page :P have a good one!

Mathematics
2 answers:
____ [38]3 years ago
6 0
1/5 x 105 = 21
1/5 x 75 = 15
QveST [7]3 years ago
5 0
The first answer is 21 and the second is 15
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-2-(-9)<br>plz show work<br><br>​
neonofarm [45]

Answer:

- 2 - (- 9) \\  =  >  - 2 + 9 \\  =  > \:  \: 7

hope that helps uhh!!

8 0
3 years ago
Read 2 more answers
Aubrey's scarf is 4 inches more than half the length
mina [271]

Answer

Tyrone's scarf is 15 inches long

Step-by-step explanation:

34-4= 30

30/2= 15

5 0
4 years ago
Prove the segments joining the midpoint of consecutive sides of an isosceles trapezoid form a rhombus. use the distance formula
riadik2000 [5.3K]
In order to prove this, we have to put the trapezoid to the coordinate system. In the attached photo you can see how it has to be put. The coordinates for the vertices of trapezoid written according to the midpoint principle. By using the distance between two points formula, we can find the coordinates for the vertices of the rhombus. 
D_{x} = \frac{-2b-2a}{2}=-b-a and D_{y}= \frac{2c+0}{2}=c. The coordinates of D is (-b-a, c)
E_{x} = \frac{-2b+2b}{2}=0 and E_{y}= \frac{2c+2c}{2}=2c. The coordinates of E is (0,2c)
Since we have the reflection in this graph, the coordinates of F is (b+a, c)
And the coordinates of G is (0,0).

Using the distance formula, we can find that 
DE= \sqrt{(-b-a)^{2}+ c^{2}}=\sqrt{(b+a)^{2} + c^{2}}
EF= \sqrt{(b+a)^{2} + c^{2} }
GF= \sqrt{(b+a )^{2} + c^{2} }
DG= \sqrt{(b+a)^{2}+ c^{2} 

Since all the sides are equal this completes our proof. Additionally, we can find the distances of EG and DF in order to show that the diagonals of this rhombus are not equal. So that it is not a square, but rhombus. 

6 0
3 years ago
Read 2 more answers
PLEASE HELP 30 POINTS.
Nookie1986 [14]

Answer:


Step-by-step explanation:

Note that the four input values, {3,4,6,11}, are all unique.  Each has exactly one y value associated with it.  This is an important criterion when we're deciding whether a relation is a function or not.

Suppose that we added one more input and its associated output:

{3,4,4,6,11}

If it happened that different values of y were associated with the two 4's, then we know immediatel that this relation is not a function.

5 0
4 years ago
A flagpole has a height of 10 yards. It will be supported by 3 cables, each of which is attached to the flagpole at a point 4 ya
Contact [7]
Pytagorean theorem

height10
attached at 10-4=6 yards from bottom
8 yards from base to away


a^2+b^2=c^2
a and b are side legnths and c=hypotonuse
so therfore we are given a and b and we must solve for c


so
6=height
8=base

6^2+8^2=c^2
36+64=c^2
100=c^2
square root
10=c

so therfor the legnth of each cable is 10 yards
3 cables so 3 times 10=30

30 yards needed

7 0
3 years ago
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