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3 years ago

Please help and if ur helpful enough there’s like a bunch of questions I need answered on my page :P have a good one!

Mathematics

2 answers:

____ [38]3 years ago

6 0

1/5 x 105 = 21
1/5 x 75 = 15

QveST [7]3 years ago

5 0

The first answer is 21 and the second is 15

You might be interested in

Simplify: 299.081+59.26-95.32-365.195

Lilit [14]

-102.174. Just plugged into a calculator

5 0

3 years ago

Convert this number expressed in standard form to scientific notation.<br><br> 28,500,000

tekilochka [14]

Answer:

2.85 × 10^7

Step-by-step explanation:

1.In scientific notation, the whole number before the decimal point shouln't be more than 10(exclude 10) or less than 1(include 1)

2.Count the digits after the decimal point to write the power.

Solution;

1. 2.85( 2 is not less than 1 as well as more than 10).

2.Since there are 7 digits after the decimal point, we should write the power 10^7.

3. Complete answer;

2.85 × 10^ 7

6 0

3 years ago

If you are eligible to help can you help me please.!

uranmaximum [27]

Answer:

The difference in the medians of both weeks is 5 minutes.

7 0

3 years ago

Solve for c<br> -38+-75c≥37

harina [27]

C= -1 because when you add 38 to the other side you are left with -75c=75 then divide by -75 and you are left with -1

3 0

3 years ago

Maci and I are making a small kite. Two sides are 10". Two sides are 5". The shorter diagonal is 6". Round all your answers to t

Art [367]

Answer:

A. 4".

B. Approximately 9.54".

C. Approximately 13.54".

Step-by-step explanation:

Please find the attachment.

Let x be the distance from the peak of the kite to the intersection of the diagonals and y be the distance from the peak of the kite to the intersection of the diagonals.

We have been given that two sides of a kite are 10 inches and two sides are 5 inches. The shorter diagonal is 6 inches.

A. Since we know that the diagonals of a kite are perpendicular and one diagonal (the main diagonal) is the perpendicular bisector of the shorter diagonal.

We can see from our attachment that point O is the intersection of both diagonals. In triangle AOD the side length AD will be hypotenuse and side length DO will be one leg.

We can find the value of x using Pythagorean theorem as:

$(AO)^2=(AD)^2-(DO)^2$

$x^{2}=5^2-3^2$

$x^{2}=25-9$

$x^{2}=16$

Upon taking square root of both sides of our equation we will get,

$x=\sqrt{16}$

$x=\pm 4$

Since distance can not be negative, therefore, the distance from the peak of the kite to the intersection of the diagonals is 4 inches.

B. We can see from our attachment that point O is the intersection of both diagonals. In triangle DOC the side length DC will be hypotenuse and side length DO will be one leg.

We can find the value of y using Pythagorean theorem as:

$(OC)^2=(DC)^2-(DO)^2$

Upon substituting our given values we will get,

$y^2=10^2-3^2$

$y^2=100-9$

$y^2=91$

Upon taking square root of both sides of our equation we will get,

$y=\sqrt{91}$

$y\pm 9.539392$

$y\pm\approx 9.54$

Since distance can not be negative, therefore, the distance from intersection of the diagonals to the top of the tail is approximately 9.54 inches.

C. We can see from our diagram that the length of longer diagram will be the sum of x and y.

$\text{The length of the longer diagonal}=x+y$

$\text{The length of the longer diagonal}=4+9.54$

$\text{The length of the longer diagonal}=13.54$

Therefore, the length of longer diagonal is approximately 13.54 inches.

3 0

3 years ago