Y *x =20
y +x =9
rewrite 1st eq. as y = 20/x
subsituute that into 2nd eq.
20/x +x =9
multiply each term by X
20 +x^2 = 9x
subtract 9x from each side:
x^2 - 9x +20 = 0
now factor:
(x-5) (x-4) = 0
solve for x
5-5 = 0
4-4 = 0
so X can be 4 or 5
replace x into equations and solve for Y
so when X = 4, Y = 5
When X = 5, Y = 4
x= 5,4
y = 4,5
5
5 x 8 = 40
6 x 1 = 6
40 / 6 = 6
= 6 2/3
(hope I'm right & this helps you!)
Answer: 571
To get this answer, we first need to compute the value of f(4). This happens when we plug x = 4 into f(x)
f(x) = 5x + 4
f(4) = 5*4+4 ... each x replaced with 4
f(4) = 20+4
f(4) = 24
Now replace every 'x' in g(x) with f(4) like so
g(x) = x^2 - 5
g(x) = ( x )^2 - 5
g(f(4)) = ( f(4) )^2 - 5 .... every x replaced with f(4)
g(f(4)) = ( 24 )^2 - 5 ... see note below
g(f(4)) = 576 - 5
g(f(4)) = 571
note: the f(4) on the right hand side of that equation is replaced with 24, because we found earlier that f(4) = 24. In other words, f(4) is the same as 24.
Answer:
2
Step-by-step explanation:
