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GREYUIT [131]
3 years ago
6

One side in a Transmission Control Protocol (TCP) connection has not been able to properly recover from a series of malformed se

gments. Which Transmission Control Protocol (TCP) flag will be used?
Computers and Technology
1 answer:
Pavel [41]3 years ago
3 0

Answer:

TCP RST flag

Explanation:

The RST is the Transmission Control Protocol, TCP Reset  package sent back to a source of an unexpected TCP packet by the host, as a response, through the same route connection.

Where one side of the TCP connection has received malformed, unexpected packets such that the TCP connection is yet to recover, the TCP reset package, RST, is sent to the source of the packets to indicate the need for the termination of the connection due to a fatal error

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What is the value of the variable index after the Python code below is executed? word = 'bAnana' index = word.find('a')
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Answer:

index = 3

Explanation:

the find() function finds the first instance of a letter or word.

'b' = 0

'A' = 1

'n' = 2

'a' = 3

'n' = 4

'a' = 5

the first instance of 'a' in  "bAnana" is found at index location 3 computer scientist start counting from zero.

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What feature allows you to access previous copies of a document on OneDrive?
irga5000 [103]

Version history feature

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3 years ago
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When engineers consider _____, they propose giving up a benefit of one proposed design in order to obtain a benefit of a differe
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5 0
3 years ago
A drowsy cat spots a flowerpot that sails first up and then down past an open window. The pot is in view for a total of 0.50 sec
GaryK [48]

Answer:

2.342m

Explanation:

Given

Time = 0.5 s

Height of Window = 2m

Because the pot was in view for a total of 0.5 seconds, we can assume that it took the cat 0.25 seconds to go from the bottom of the window to the top

Using this equation of motion

S = ut - ½gt²

Where s = 2

u = initial velocity = ?

t = 0.25

g = 9.8

So, we have.

2 = u * 0.25 - ½ * 9.8 * 0.25²

2 = 0.25u - 0.30625

2 + 0.30625 = 0.25u

2.30625 = 0.25u

u = 2.30625/0.25

u = 9.225 m/s ------------ the speed at the bottom of the pot

Using

v² = u² + 2gs to calculate the height above the window

Where v = final velocity = 0

u = 9.225

g = 9.8

S = height above the window

So, we have

0² = 9.225² - 2 * 9.8 * s

0 = 85.100625 - 19.6s

-85.100625 = -19.6s

S = -85.100625/19.6

S = 4.342

If 4.342m is the height above the window and the window is 2m high

Then 4.342 - 2 is the distance above the window

4.342 - 2 = 2.342m

6 0
3 years ago
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