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2 years ago

Please help me

Mathematics

1 answer:

nikklg [1K]2 years ago

4 0

Answer:

2. $1,100 in clothing sales gives Rachel a $260 paycheck

3 $.2,200 in clothing sales gives Rachel a $370 paycheck

5. $10,800 in clothing sales gives Rachel a 1,230 paycheck

Step-by-step explanation:

Here is the complete question :

Rachel works for a clothing store. She is $150 paid every week plus a 10% commission on any clothes that she sells. Which of the following is true in regards to Rachel's weekly paycheck? Chose three correct answers.

1. $100 in clothing sales gives Rachel a $250 paycheck

2. $1,100 in clothing sales gives Rachel a $260 paycheck

3 $.2,200 in clothing sales gives Rachel a $370 paycheck

4. $ 4,200 in clothing sales gives Rachel a $420 paycheck

5. $10,800 in clothing sales gives Rachel a 1,230 paycheck

6. $ 16,000 in clothing sales gives Rachel a 1,450 paycheck

The equation representing Rachel's paycheck = amount she earns every month + commission

If she makes $100 in clothing sales, her paycheck = $150 + (0.1 x 100) = $160

If she makes $1100 in clothing sales, her paycheck = $150 + (0.1 x 1100) = $260

If she makes $2200 in clothing sales, her paycheck = $150 + (0.1 x 2200) = $370

If she makes $4200 in clothing sales, her paycheck = $150 + (0.1 x 4200) = $570

If she makes $10800 in clothing sales, her paycheck = $150 + (0.1 x 10800) = $1230

If she makes $16000 in clothing sales, her paycheck = $150 + (0.1 x 16000) = $1750

thus the correct options are 2,3,5

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a) 0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

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Step-by-step explanation:

For itens a and b, we use conditional probability.

For item c, we use the binomial distribution along with the conditional probability.

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

a) If it has an emergency locator, what is the probability that it will not be discovered?

Event A: Has an emergency locator

Event B: Not located.

Probability of having an emergency locator:

66% of 72%(Are discovered).

20% of 100 - 72 = 28%(not discovered). So

$P(A) = 0.66*0.72 + 0.2*0.28 = 0.5312$

Probability of having an emergency locator and not being discovered:

20% of 28%. So

$P(A cap B) = 0.2*0.28 = 0.056$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.056}{0.5312} = 0.105$

0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) If it does not have an emergency locator, what is the probability that it will be discovered?

Probability of not having an emergency locator:

0.5312 of having. So

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34% of 72%. So

$P(A \cap B) = 0.34*0.72 = 0.2448$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.2448}{0.4688} = 0.522$

0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

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0.5312 probability of having the emergency recorder.

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66% of 72%. So

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Step-by-step explanation:

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I'm not sure but I think 39% is the answer. Better to google it ;)

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2 years ago