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ch4aika [34]
2 years ago
7

-9(4p-6q)+8q-7(3q-3p) how would I rewrite in simplest terms

Mathematics
2 answers:
koban [17]2 years ago
8 0

Answer:

The answer is - 15p + 41q

Step-by-step explanation:

The explanation is on the picture attached

nadya68 [22]2 years ago
4 0

Answer: -15p + 41q

Step-by-step explanation:

Problem: -9(4p-6q) + 8q- 7(3q - 3p)

1. Expand by distributing terms

−(36p−54q) + 8q − 7(3q − 3p)

2. Expand by distributing terms

−(36p−54q) + 8q − (21q − 21p)

3. Remove parenthesis

−36p + 54q + 8q − 21q + 21p

4. Collect like terms

(−36p + 21p) + (54q + 8q − 21q)

5. Simplify

-15p + 41q

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Read 2 more answers
Graph triangle RST with vertices R(3, 7), S(-5, -2), and T(3, -5) and its image after a reflection over x = -3.​
kirill115 [55]

Given:

The vertices of a triangle are R(3, 7), S(-5, -2), and T(3, -5).

To find:

The vertices of the triangle after a reflection over x = -3 and plot the triangle and its image on the graph.

Solution:

If a figure reflected across the line x=a, then

(x,y)\to (-(x-a)+a,y)

(x,y)\to (-x+a+a,y)

(x,y)\to (2a-x,y)

The triangle after a reflection over x = -3. So, the rule of reflection is

(x,y)\to (2(-3)-x,y)

(x,y)\to (-6-x,y)

The vertices of triangle after reflection are

R(3,7)\to R'(-6-3,7)

R(3,7)\to R'(-9,7)

Similarly,

S(-5,-2)\to S'(-6-(-5),-2)

S(-5,-2)\to S'(-6+5,-2)

S(-5,-2)\to S'(-1,-2)

And,

T(3,-5)\to T'(-6-3,-5)

T(3,-5)\to T'(-9,-5)

Therefore, the vertices of triangle after reflection over x=-3 are R'(-9,7), S'(-1,-2) and T'(-3,-5).

3 0
3 years ago
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