Answer:
9.9
Step-by-step explanation:
\text{Volume of Hemisphere}\text{:}
Volume of Hemisphere:
\,\,257
257
\text{Volume of Sphere}\text{:}
Volume of Sphere:
\,\,514
514
Double volume of hemisphere to get volume of the entire sphere
\text{Volume of a Sphere:}
Volume of a Sphere:
V=\frac{4}{3}\pi r^3
V=
3
4
πr
3
514=
514=
\,\,\left(\frac{4}{3}\pi\right) r^3
(
3
4
π)r
3
514=
514=
\,\,(4.1887902)r^3
(4.1887902)r
3
Evaluate 4/3pi in calc
\frac{514}{4.1887902}=
4.1887902
514
=
\,\,\frac{(4.1887902)r^3}{4.1887902}
4.1887902
(4.1887902)r
3
Evaluate \frac{4}{3}\pi
3
4
π in calc
122.7084611=
122.7084611=
\,\,r^3
r
3
\sqrt[3]{122.7084611}=
3
122.7084611
=
\,\,\sqrt[3]{r^3}
3
r
3
Cube root both sides
4.9692575=
4.9692575=
\,\,r
r
\text{Then the diameter equals }9.938515
Then the diameter equals 9.938515
diameter is radius times 2
\text{Final Answer:}
Final Answer:
d\approx 9.9\text{ m}
d≈9.9 m
Round to nearest tenth
Answer:
1 1/2 lbs
Step-by-step explanation:
Answer:
Check pdf
Step-by-step explanation:
Complete question:
A project is graded on a scale of 1 to 5. If the random variable, X, is the project grade, what is the mean of the probability
distribution below?
Grade(X)_____ 1_____2_____3_____4_____5
Frequency____3 _____5____ 9 ____ 5 ____ 3
P(X) : _______ 0.1 ___0.2 ___0.4 ___ 0.2 __0.1
Answer:
3
Step-by-step explanation:
Given the probability distribution :
Grade(X)_____ 1_____2_____3_____4_____5
Frequency____3 _____5____ 9 ____ 5 ____ 3
P(X) : _______ 0.1 ___0.2 ___0.4 ___ 0.2 __0.1
The mean of the distribution :
Σ(X * P(X)) :
(1*0. 1) + (2 * 0.2) + (3 * 0.4) + (4 * 0.2) + (5 * 0.1)
0.1 + 0.4 + 1.2 + 0.8 + 0.5
= 3
