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3 years ago

What is the first step in the decision-making process, and why is it important?

1 answer:

7 0

The first step in making the right decision is recognizing the problem or opportunity and deciding to address it. Determine why this decision will make a difference to your customers or fellow employees.

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List all the factors of 19. Tell whether 19 is prime or composite.

andreyandreev [35.5K]

Answer:

19 is a prime number, thus making the only factors 1, 2, 19. (Not necessary to include 1)

Step-by-step explanation:

8 0

3 years ago

Please help on this problem

lubasha [3.4K]

-6 is the answer since 6*-1 is -6

4 0

3 years ago

name a factor pair for a rectangle that has an area of 50 sq. cm.and a perimeter greater than 100 cm.

ioda

<span>a rectangle of dimensions 1 cm * 50 cm has a perimeter of 102 cm.</span>

7 0

3 years ago

5p - 14 = 8p + 4<br><br> Explain

grigory [225]

1: we bring all the x to one member, changing its sign (I use x, consider it a p)
$5x - 8x - 14 = + 4$

2 we bring all the non-x to the other member
$5x - 8x = + 14 + 4$
3 we solve the members
$(5 - 8)x = - 3x$
$( + 14 + 4) = + 18$
4 we divide 18 by -3
$- 3x = + 18$
$x = 18 \div - 3$
$18 \div - 3 = - 5$
$x = - 5$
my English is so bad lol

5 0

3 years ago

Read 2 more answers

Easy math, but not sure what I did wrong.

Ierofanga [76]

Answer:

Step-by-step explanation:

In his 5th year, he took 3 times as many exams as the first year. So the number of exams taken in the 5th year must be a multiple of 3.

If a₁ = 1, then a₅ = 3. However, this isn't possible because we need 4 integers between them, and a sum of 31.

If a₁ = 2, then a₅ = 6. Same problem as before.

If a₁ = 3, then a₅ = 9. This is a possible solution.

If a₁ = 4, then a₅ = 12. If we assume a₂ = 5, a₃ = 6, and a₄ = 7, then the sum is 34, so this is not a possible solution.

Therefore, Alex took 3 exams in his first year and 9 exams in his fifth year. So he took 19 exams total in his second, third, and fourth years.

3 < a₂ < a₃ < a₄ < 9

If a₂ = 4, then a₃ = 7 and a₄ = 8.

If a₂ = 5, then a₃ = 6 and a₄ = 8.

If a₂ = 6, then there's no solution.

So Alex must have taken 8 exams in his fourth year.

4 0

3 years ago