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Alisiya [41]
3 years ago
15

6.

Mathematics
2 answers:
Vesnalui [34]3 years ago
8 0

Answer:

B. Yes, there is no value in the domain that corresponds to more than one value of the range.

Step-by-step explanation:

Since there is one value of  

y

for every value of  

x

in  ( 1 , 2 ) , ( 2 , 3 ) , ( 3 , 4 ) , ( 4 , 5 ) , ( 5 , 6 )

, this relation is a function.

The relation is a function.

Yes, there is no value in the domain that corresponds to more than one value of the range. Hope I helped

The correct option is

(2). Yes, there is no value in the domain that corresponds to more than one value of the range.

Step-by-step explanation:  We are given to check whether the following relation is a function or not.

We know that,

the first element of each ordered pair in the relation above makes the domain and the second element of each ordered pair makes the range.

So, the domain will be  

and the range will be  

A RELATION will be a function if each value in the domain correspond to one and only one value in the range.

Since, in the set R, there is no value in the domain that corresponds to more than one value of the range, so

The given relation 'R' is a FUNCTION.

Thus, the correct option is

(2). Yes, there is no value in the domain that corresponds to more than one value of the range.

Dafna1 [17]3 years ago
5 0

Answer:

its a function so answer is b

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given;

F(x) = 6x³  +  19x²   +   17x   +  3

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Using long division method;

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                                 ------------------------------------

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                             -  (6x³   +   9x²)

                                ----------------------------------------

                                               10x²    +    17x   +  3

                                          -   (10x²     + 15x)

                                             -------------------------------

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                                                               - (2x   +  3)

                                                                 ---------------

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Thus, \frac{6x^3 \ + \ 19x^2 \ + \ 17x \ + \ 3}{2x \ + \ 3}  \ = 3x^2 \ + \ 5x \ + \ 1

                       

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Hope this helped!
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