Hello :
<span>the general term equation, an, for the arithmetic sequence is :
An = A1+d(n-1)
A1 : the first term and : d the common diference
in this exercice :
A1 = 9
d =(-3)-(1) =(1)-(5) =(5) -(9) = -4
An = 9-4(n-1)
An = -4n +13</span>
Slope of the line = (13-4)/(1- -2) = 9/3 = 3
y - y1 = m(x - x1)
y - 4 = 3(x - -2)
y- 4 = 3x + 6
y = 3x + 10 Answer
(2.3)(-5.0)
-(2.3x0.5)
=-1.15 or as a fraction -23/20
Hope this helps
Step-by-step explanation:
Correct option is
C
0≤r<b
If r must satisfy0≤r<b
Proof,
..,a−3b,a−2b,a−b,a,a+b,a+2b,a+3b,..
clearly it is an arithmetic progression with common difference b and it extends infinitely in both directions.
Let r be the smallest non-negative term of this arithmetic progression.Then,there exists a non-negative integer q such that,
a−bq=r
=>a=bq+r
As,r is the smallest non-negative integer satisfying the result.Therefore, 0≤r≤b
Thus, we have
a=bq1+r1, 0≤r1≤b
