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Gnom [1K]
2 years ago
10

Can someone pls help me

Mathematics
1 answer:
Alina [70]2 years ago
4 0

Answer:

Sure, what do you need?

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Which quadrant of the coordinate plane would you use to graph time and distance?
Tema [17]
The second quadrant
6 0
3 years ago
Read 2 more answers
Y=-1\4z+5 please grqph
svet-max [94.6K]

Answer

Attached the graph

Step by step explanation

Y = -1/4z + 5

Let's form the table values

Here z is the independent variable and y is the dependent values.

Let's take z = -1, 0, 1, 2 and find the corresponding y-values

<u>z                           y</u>

-1                         5.25

0                          5

1                           4.75

2                           4.5

Now let's plot the points and draw the graph.

Here is the graph.

5 0
3 years ago
What is the solution of 6(3-2x)=54?
notka56 [123]
Hello!

You solve this algebraically

6(3 - 2x) = 54

distribute the 6

18 - 12x = 54

Subtract 18 from both sides

-12x = 36

Divide both sides by -12

x = -3

The answer is -3

Hope this helps!
3 0
3 years ago
Read 2 more answers
How would I solve this i got 4.5
Aliun [14]

Answer:

up \: is \: the \: angle \: bisector \\ so \: 54 = 5x - 6 \\ 5x = 54 + 6 \\ 5x = 60 \\ x =  \frac{60}{5}  = 12 \\ thank \: you

6 0
2 years ago
Read 2 more answers
Select the correct answer from each drop-down menu.
finlep [7]

Answer:

Coordinates of point B are (10,-4)

Coordinates of point D are (3.6,-0.4)

Step-by-step explanation:

1) Point C(3.6, -0.4) divides in the ratio 3 : 2. If the coordinates of A are (-6, 5), the coordinates of point B are ____

Let the coordinates of B be (x_2,y_2)

Coordinates of A =(x_1,y_1)=(-6,5)

Coordinates of C=(x,y)=(3.6,-0.4)

We will use section formula over here

x=\frac{mx_2+nx_1}{m+n} , y = \frac{my_2+ny_1}{m+n}

m:n=3:2

3.6=\frac{3x_2+2(-6)}{3+2} , -0.4=\frac{3y_2+2(5)}{3+2}3.6 \times 5 = 3x_2-12, -0.4 \times 5 = 3y_2+10\\18+12=3x_2 , -2=3y_2+10\\30=3x_2 , -12=3y_2\\10=x_2, -4=y_2\\

Coordinates of B = (10,-4)

2)If point D divides in the ratio 4 : 5, the coordinates of point D are ____

(fraction)

Let the coordinates of D be (x,y)

Coordinates of A =(x_1,y_1)=(-6,5)

Coordinates of B=(x_2,y_2)=(10,-4)

We will use section formula over here

x=\frac{mx_2+nx_1}{m+n} , y = \frac{my_2+ny_1}{m+n}

m:n=3:2

x=\frac{3(10)+2(-6)}{3+2} , y=\frac{3(-4)+2(5)}{3+2}\\x=3.6,y=-0.4

Coordinates of point B are (10,-4)

Coordinates of point D are (3.6,-0.4)

4 0
2 years ago
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