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3 years ago

6

Luke is taller than leo.Leo is not as tall as luke but taller than George. John is not as tall as Leo but taller than George. Wh

o is the tallest of them all?

1 answer:

jarptica [38.1K]3 years ago

8 0

Answer:

LEO

Step-by-step explanation:

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Can someone answer this please and please answer it correctly please show work I need it today

Lostsunrise [7]

Answer: 45

Step-by-step explanation:

Total number of 8th graders that signed up = 30

9 dropped out. So the total number 8th graders on board the game

= 30 - 9 = 21

46 2/3 % of the club are 8th graders i.e 21

Let T be the total number of students in the club

46 2/3 % T = 21

(140/3)% T = 21

(140/300)T = 21

T = (21x300)/140 = 45

Therefore, there are 45 students on the club

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Tan^2 A/1+cot^2 A + cot^2 A/1+tan^2 A=sec^2 A cosec^2 A-3

omeli [17]

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$=\frac{(tanx+cotx)^2+(tan^2x-cot^2x)^2}{(tanx+cotx)^2}=\frac{(tanx+cotx)^2}{(tanx+cotx)^2}+\frac{(tan^2x-cot^2x)^2}{(tanx+cotx)^2}\\\\=1+\frac{(tanx-cotx)^2(tanx+cotx)^2}{(tanx+cotx)^2}=1+(tanx-cotx)^2\\\\=1+tan^2x-2tanx\ cotx+cot^2x=tan^2x+cot^2x+1-2\\\\=\left(\frac{sinx}{cosx}\right)^2+\left(\frac{cosx}{sinx}\right)^2-1=\frac{sin^2x}{cos^2x}+\frac{cos^2x}{sin^2x}-1=\frac{sin^4x+cos^4x}{sin^2x\ cos^2x}-1$

$=\frac{(sin^2x)^2+2sin^2x\ cos^2x+(cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{(sin^2x+cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{1}{sin^2x\ cos^2x}-\frac{2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1}{sin^2x}\cdot\frac{1}{cos^2x}-2-1\\\\=cosec^2x\cdot sec^2x-3=sec^2x\ cosec^2x-3=R$

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