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Natasha_Volkova [10]
3 years ago
7

please help me i don’t know how to do this. if you do know, please explain how you did it bc i have so many more of these to do,

ty!:)

Mathematics
1 answer:
Alex73 [517]3 years ago
6 0

Answer:

Blue: y = x² + 3

Purple: y = (x + 4)²

Step-by-step explanation:

The parabolas are "transformed", meaning they have been shifted on the coordinate grid. All parabolas will have the equation of "y = x²", any additional transformation will add onto that.

Blue: Looking at the red parabola, its lowest point is only three units down from the blue's lowest points. Meaning the blue parabola went only three units up. So you only have to do the "+ 3" in the equation.

Purple: Like in blue, we're gonna look at the purple's lowest point and compare it to red's lowest point. The purple parabola seems to have shifted only four units to the left. Though, instead of adding onto the equation like in the blue parabola, any changes on the x-axis will be put into parenthesis. IN ADDITION, the sign will be the opposite of what it is on the coordinate grid. For example, the purple parabola is on the -4 of the x-axis. Instead of putting "(x - 4)", we put "(x + 4)".

Try the next two problems on your own. They will be similarly structured to the two answers above. If you need more help, lemme know. :)

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lyudmila [28]
Check the picture below.

so.. simply, use the distance formula, to get their length an add them up, and that's the perimeter of the polygon.


\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -1}}\quad ,&{{ 2}})\quad 
%  (c,d)
&({{ 2}}\quad ,&{{ 4}})\\
&({{ 2}}\quad ,&{{ 4}})\quad 
%  (c,d)
&({{ 3}}\quad ,&{{ -2}})\\
&({{ 3}}\quad ,&{{ -2}})\quad 
%  (c,d)
&({{ -2}}\quad ,&{{ -3}})\\
&({{ -2}}\quad ,&{{ -3}})\quad 
%  (c,d)
&({{ -1}}\quad ,&{{ 2}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}

\bf -------------------------------\\\\
d=\sqrt{[2-(-1)]^2+(4-2)^2}\implies d=\sqrt{(2+1)^2+(2)^2}
\\\\\\
d=\sqrt{3^2+2^2}\implies \boxed{d=\sqrt{13}}\\\\
-------------------------------\\\\
d=\sqrt{(3-2)^2+(-2-4)^2}\implies d=\sqrt{1^2+(-6)^2}\implies \boxed{d=\sqrt{37}}\\\\
-------------------------------\\\\
d=\sqrt{(-2-3)^2+[-3-(-2)]^2}\implies d=\sqrt{(-5)^2+(-3+2)^2}
\\\\\\
d=\sqrt{(-5)^2+(-1)^2}\implies \boxed{d=\sqrt{26}}

\\\\
-------------------------------\\\\
d=\sqrt{[-1-(-2)]^2+[2-(-3)]^2}\implies d=\sqrt{(-1+2)^2+(2+3)^2}
\\\\\\
d=\sqrt{(1)^2+(5)^2}\implies \boxed{d=\sqrt{26}}

so, those are their lengths, sum them all up, that's the polygon's perimeter.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Now I'll try 20. I got 8420. Looks like the number is between 5 and 20.

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Answer:

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Step-by-step explanation:

The measures of water tank is 8m x 5m x 3m.

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Hence, the capacity of the tank when full is 120 cubic m.

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