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olga nikolaevna [1]

3 years ago

7

-2 - 10j = -9j -3Is that no solutionone solutioninfinitely many solution

1 answer:

jasenka [17]3 years ago

4 0

It's one solution.

no matter how you solve it, it will equal j = 1.

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Which value of a from the set {3, 4, 5, 6} makes this equation true? a + 4(a − 5) = 5

elixir [45]

A + 4(a - 5) = 5
a + 4a - 20 = 5
5a = 5 + 20
5a = 25
a = 25/5
a = 5 <====

5 0

3 years ago

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Please help me with this math question!

MatroZZZ [7]

Harry's trainer recommends Harry drink
8*(8 oz) = 64 oz
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4 years ago

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Gala2k [10]

Answer: 8$

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7 0

3 years ago

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Sin (3x) dx = ?<br> find the integral

AVprozaik [17]

Answer:

$\displaystyle \displaystyle \int {sin(3x)} \, dx = \frac{-cos(3x)}{3} + C$

General Formulas and Concepts:

<u>Calculus</u>

Antiderivatives - Integrals

Integration Constant C

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Trig Integration: $\displaystyle \int{sin(x)} \, dx = -cos(x) + C$

U-Substitution

Step-by-step explanation:

<u>Step 1: Define</u>

$\displaystyle \int {sin(3x)} \, dx$

<u>Step 2: Identify Substitution Variables</u>

u = 3x

du = 3dx

<u>Step 3: Integrate</u>

[Integral] Rewrite: $\displaystyle \frac{1}{3}\int {3sin(3x)} \, dx$
[Integral] U-Substitution: $\displaystyle \frac{1}{3}\int {sin(u)} \, du$
[Integral] Trig Integration: $\displaystyle \frac{1}{3}[-cos(u)] + C$
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[Expression] Back-Substitute: $\displaystyle \frac{-cos(3x)}{3} + C$

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3 years ago

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____ [38]

L = rc
where c = angle in radians , r = radius and l = length of the arc
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5.4 = 6 r
r = 0.9 radians
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0.9

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3 years ago