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Vedmedyk [2.9K]
2 years ago
6

Show that the function has at least one zero between x=1 and x=2

Mathematics
1 answer:
ANTONII [103]2 years ago
7 0

Answer:

See Below.

Step-by-step explanation:

We are given the function:

\displaystyle f(x) = 7x^5-9x^4-x^2

And we want to show that it has at least one zero between <em>x</em> = 1 and <em>x</em> = 2.

Because the function is a polynomial, it is everywhere continuous.

Evaluate the function at <em>x</em> = 1 and <em>x</em> = 2:

\displaystyle \begin{aligned} f(1) & = 7(1)^5 - 9(1)^4 - (1)^2 \\ \\ & = -3\end{aligned}

And:

\displaystyle \begin{aligned} f(2) & = 7(2)^5 - 9(2)^4 - (2)^2 \\ \\ & = 76 \end{aligned}

Therefore, because the function changes signs from <em>x</em> = 1 to <em>x</em> = 2 and is continuous on the interval [1, 2], by the intermediate value theorem, there must exist at least one zero in the interval.

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Express using algebra. Five more than twice x.
Anarel [89]

Answer:

2x+ 5

Step-by-step explanation:

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3 years ago
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Which choice is equivalent to the expression below when y2 0?<br> √y^2 + √16y^3 – 4y√y
DanielleElmas [232]

Answer:

Option C.

Step-by-step explanation:

We start with the expression:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

where y > 0. (this allow us to have y inside a square root, so we don't mess with complex numbers)

We want to find the equivalent expression to this one.

Here, we can do the next two simplifications:

\sqrt{16*y^3} = \sqrt{16} \sqrt{y^3} = 4*\sqrt{y^3}

And:

y*\sqrt{y} = \sqrt{y^2} *\sqrt{y} = \sqrt{y^2*y} = \sqrt{y^3}

If we apply these two to our initial expression, we can rewrite it as:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

\sqrt{y^3}  + 4*\sqrt{y^3} - 4\sqrt{y^3} = \sqrt{y^3}

Here we can use the second simplification again, to rewrite:

\sqrt{y^3} = y*\sqrt{y}

So, concluding, we have:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y} = y*\sqrt{y}

Then the correct option is C.

8 0
3 years ago
A rectangle has a length that is 8 less than its width, w. The perimeter is 52. Which equation can be used to determine its
Juliette [100K]

Answer:

2(w-8) +2w=52

its perimeter so u multiply everything by 2 and since u dont know the length but know its 8 less u subtract by width

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3 years ago
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If Harriet rolls a number cube 39 times,how many times can she expect to roll a 3 or a 4?
hram777 [196]
Usually, cubes have 6 sides on them, so the chances of first rolling either 3 or a 4 is 1/3th of a chance. Then, if she rolls it 39 times, I'd do 1/3 of 39, and get 13. She can expect 13 times to roll a 3 or a 4.
3 0
4 years ago
What is the logarithmic form of 13² = 169?
LuckyWell [14K]

The logarithmic form of  13² = 169 is ㏒₁₃ 169 = 2

<h3>How to determine the logarithmic form</h3>

Using the logarithmic rule , we have that

㏒ₙn = bⁿ

Given 13² = 169

It is important to  note that it can be written either in the logarithmic form or in the index form.

In this case, we have written in the index form as .

㏒₁₃ 169 = 2

Thus, the logarithmic form of  13² = 169 is ㏒₁₃ 169 = 2

Learn more about logarithm form here:

https://brainly.in/question/51458041

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8 0
2 years ago
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