Answer:
a:b = 2
Step-by-step explanation:
Here we need to operate with terms in order to arrive to a ratio a:b (or a/b).
We have:
2a−b/6 = b/3
Lets sum b/6 in both sides:
2a−b/6 + b/6 = b/3 + b/6
2a = b/3 + b/6
Now, we can multiply and divide b/3 by 2 to make a 6 appear on the denominator and sum it with b/6, this is, use common denominator:
2a = b/3*(2/2) + b/6
2a = 2b/6 + b/6
2a = 3b/6
2a = b/2, as 3/6 = 1/2
Now lets divide both sides by b to make an a/b appear:
2a/b = (b/2)/b
2a/b = 1/2
Finally, multiply both sides by (1/2) or divide by 2:
(2a/b)/2 = 2
a/b = 2
This is, a is twice as b. If b is 1 so a is 2; if b is 45 so a is 90, and so on.
Step-by-step explanation:
4^5 (-2)^9/4^8 (-2)^3
= 4^(5 - 8) (-2^(9 - 3))
= 4^-3 (-2^6)
= (-2)^6/4^3
1). (-2)^a/4^b
a = 6, b = 3
2). c/d
c = -2, d = 4
Answer:
68°
Step-by-step explanation:
Here,
- Two supplementary angles are (2x – 8)° and (3x - 2)°.
As we know that the sum of two supplementary angles are 180°. So,
→ (2x – 8)° + (3x – 2)° = 180°
→ 2x° – 8° + 3x° – 2° = 180°
→ 5x° – 10° = 180°
→ 5x° = 180° + 10°
→ 5x° = 190°
→ x = 190° ÷ 5°
→ <u>x</u><u> </u><u>=</u><u> </u><u>3</u><u>8</u><u>°</u>
Supplementary angles are,
→ 2(38°) – 8
→ (76 – 8)°
→ 68°
→ 3(38°) – 2
→ (114 – 2)°
→ 112°
Therefore, the measure of the smaller angle is 68°.
Answer:
C=5
Step-by-step explanation:
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Answer:
The sweat chloride reference value is less than 30 mmol/L. A value of more than 60 mmol/L of chloride in the sweat is consistent with a diagnosis of cystic fibrosis. The values of 30-60 mEq/L may represent heterozygous carriers, these carriers cannot be accurately identified with a sweat chloride test.
