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NikAS [45]
3 years ago
11

Solve for -5v4(-31)​

Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
6 0

Answer:

155v^4

Step-by-step explanation:

dedylja [7]3 years ago
6 0

Answer:

620v

Step-by-step explanation:

-20v(-31)

-20×v×(-31)

-20v×-31

620v

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Is 0.07 less than 0.06
Kobotan [32]
No, .007 is not less than .006. Not only is the decimal form evidence of these integers, but writing them as a percentage can also decipher the question.

Since .007 equals to 7% (0.07 = 7/100) and 0.06 equals to 6% (0.06 = 6/100) then 7% is greater than 6%, therefore, answering you question.
8 0
4 years ago
The perimeter of a yard is 25 yards. if the length of the yard is 5, what is the width of the yard?
irina [24]

Answer:

the width would be 7.5

Step-by-step explanation:

6 0
3 years ago
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A spinner can land on either red, blue, green, or yellow (the wedges are the same size). you spin twice. what is the probability
melisa1 [442]
There are four (4) colors to choose from. The number of sample space is equal to 4. With the condition given in this item, the probability of landing on blue on the first spin is equal to 1/4. Similarly, the probability of landing on yellow on the second spin is 1/4. 

            P = (1/4)(1/4)
  
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Answer: 1/16
5 0
4 years ago
Prove that: (secA-cosec A) (1+cot A +tan A) =( sec^2A/cosecA)-(Cosec^2A/secA)<br>​
Ksju [112]

Step-by-step explanation:

(\sec A - \csc A)(1 + \cot A + \tan A)

=(\sec A - \csc A)\left(1 + \dfrac{\cos A}{\sin A} + \dfrac{\sin A}{\cos A} \right)

=(\sec A - \csc A)\left(1 + \dfrac{\cos^2 A + \sin^2 A}{\sin A\cos A} \right)

=(\sec A - \csc A)\left(\dfrac{1 + \sin A \cos A}{\sin A \cos A} \right)

=\left(\dfrac{\frac{1}{\cos A} - \frac{1}{\sin A}+\sin A - \cos A}{\sin A\cos A}\right)

=\dfrac{\sin A - \sin A \cos^2A - \cos A + \cos A\sin^2A}{(\sin A\cos A)^2}

=\dfrac{\sin A(1 - \cos^2A) - \cos A (1 - \sin^2 A)}{(\sin A\cos A)^2}

=\dfrac{\sin^3A - \cos^3A}{\sin^2A\cos^2A}

=\dfrac{\sin A}{\cos^2A} - \dfrac{\cos A}{\sin^2A}

=\left(\dfrac{1}{\cos A}\right)\left(\dfrac{\sin A}{1}\right) - \left(\dfrac{1}{\sin^2A}\right) \left(\dfrac{\cos A}{1}\right)

=\sec^2A\csc A -  \csc^2A\sec A

5 0
3 years ago
1. The midpoint of the segment joining points (a, b) and ( j, k) is: a. (j-a,k-b) b. ((j-a)/2,(k-b)/2) c. (j+a,k+b) d. ((j+a)/2,
harkovskaia [24]
1. The midpoint of the segment joining points (a, b) and ( j, k) is ((j+a)/2,(k+b)/2)

2. Let the coordinate of H be (a, b)
T(0, 4) = ((a + 0)/2, (b + 2)/2)
(a + 0)/2 = 0 => a + 0 = 0 => a = 0
(b + 2)/2 = 4 => b + 2 = (2 x 4) = 8 => b = 8 - 2 = 6
Therefore, the cordinate of H is (0, 6)

3. Point (-4, 3) lies in Quadrant II

4. Point (6, 0) lies on the x-axis

5. Any line with no slope is parallel to the y-axis

7. a is the value of the x-coordinate.
5a + 3 = 8
5a = 8 - 3 = 5
a = 5/5 = 1
a = 1

8. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => a = -5 and b = 7.
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9. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => r = 6.
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10. If the equation of a circle is (x - 2)^2 + (y - 6)^2 = 4, the center is point (2, 6).
True

7 0
4 years ago
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