In which quadrants does sin and cos have opposite signs.

1 answer:

8 0

Quadrants 2 and 4 because in quadrant 2, cosine is negative and sin is positive, while in quadrant 4, cosine is positive and sin is negative

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Step-by-step explanation:

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Find the value of angel 0 to the nearest 10th<br>

BaLLatris [955]

Answer: 36.9

Step-by-step explanation:

For this question you have to find out whether you are using Sin, Cos or Tan.

To work out which one you are using you can use SOH CAH TOA to help you.

SOH- The 'S' is for Sin, the 'O' and the 'H' is for Opposite over Hypotenuse.

CAH- The 'C' is for Cos and the 'A' and the 'H' is for Adjacent over Hypotenuse.

TOA- The 'T' is for Tan, the 'O' and the 'A is for Opposite over Adjacent.

As you have the Opposite (the side opposite the angle we're looking for) and the Adjacent (the side next to the angle were looking for) we would be using Tan.

So first you would have to write:

Tanθ=3/4

Then because we want Theta (θ) on it's own we would have to do the inverse to 'undo' the equation. Tan-1 is the inverse of Tan.

θ=Tan-1 3/4

To find the answer you would have to put it in your calculator.

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Hope this helps :)

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The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet

vladimir1956 [14]

$\bf s(t)=\sqrt{t^3+1}
\\\\\\
\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)
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