Determine when domain increases

A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random

Yuliya22 [10]

Answer:

b) independent samples t-test

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

Step-by-step explanation:

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2\neq 0$

Our notation on this case :

$n_1 =5$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

We can calculate the mean and deviation for eaach group with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_1 =5.92$ represent the sample mean for the group 1

$\bar X_2 =5.74$ represent the sample mean for the group 2

$s_1=1.88$ represent the sample standard deviation for group 1

$s_2=1.81$ represent the sample standard deviation for group 2

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}$

And now we can calculate the statistic:

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

The degrees of freedom are given by:

$df=5+5-2=8$

And now we can calculate the p value using the altenative hypothesis:

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

7 0

3 years ago

A Store owners offers a discount of 20% off the regular price of all jackets. Jessica has a coupon that gives her an additional

Deffense [45]

Answer:

$63

Step-by-step explanation:

The store is 20% off, Jessica has a coupon that is 5% off add that together and it's 25% off. $84 - 25% = $63

3 0

3 years ago

George is cooking an elaborate meal. He can only cook one thing at a time in his microwave oven. His turkey takes 90 minutes; t

AysviL [449]

<h2>Answer :</h2>

He need 111.75 minutes to cook the meal
He need to start at 2.08.15 P.M. in order to complete the cooking at 4 P.M.

<h2>Step-by-step explanation :</h2><h3>Known :</h3>

George can only cook one thing at a time
Turkey takes 90 minutes to cook
Pumpkin pie takes 20 minutes to cook
Rolls take 60 seconds to cook
A cup of coffee takes 45 seconds to heat

<h3>Asked :</h3>

Time needed to cook the meal
Time he need to start in order to complete the cooking at 4 P.M.

<h3>Completion :</h3>

Let's convert all the seconds to minutes. We know that 60 seconds is equal to one minute. So,

60 seconds = 1 minutes

45 seconds = 45/60 minutes = 0.75 minutes

Time needed = Turkey + Pumpkin pie + Rolls + Coffee

Time needed = 90 + 20 + 1 + 0.75

Time needed = 111.75 minutes

Then, we'll calculate the time he need to start in order to complete the cooking at 4 P.M. First, let's convert the minutes to clock format.

111.75 minutes = 1 hour and 51.75 minutes

111.75 minutes = 1 hour and 51 minutes and 45 seconds

Lastly, calculate the time he need to start in order to complete the cooking at 4 P.M.

4h 0m 0s - 1h 51m 45s = 2h 8m 15s

<h3>Conclusion :</h3>

He need 111.75 minutes to cook the meal
He need to start at 2.08.15 P.M. in order to complete the cooking at 4 P.M.

5 0

2 years ago

A gardener sold 72 apples from the crop which was 12 % of the total

Westkost [7]

Divide the number sold by the percentage:

72 / 0.12 = 600

Total crop was 600 apples.

7 0

3 years ago

Read 2 more answers

Help me help me math question help me emerge

ioda

Answer:

Step-by-step explanation:

√13.7/(3.05^2+2.6)

8 0

3 years ago