Break the problem into two parts: 1) the area of the this isosceles triangle whose hypotenuse is AB and 2) the area of the semicircle whose diameter is AB.
The triangle is isosceles because the lengths of the two shorter legs are the same (2 meters). Use the Pythagorean Theorem to find the length of the hypotenuse of this triangle. (AB)^2 = (2 m)^2 + (2 m)^2, or 8 m^2. Thus, AB = sqrt(8 m^2), or 2sqrt(2). This AB is also the base of the triangle. What is the area of the triangle?
Next, noting that the diameter AB of the semicircle is 2sqrt(2) and the radius is just sqrt(2), find the area of the semicircle. The area of a circle of radius r
is pi*r^2; here it's pi*(sqrt 2)^2, or pi*2, or 2pi.
Add the area of the triangle to this area of the semicircle (2pi) to find the total area of the figure.
Hint: the area of a triangle is (bh)/2, where h is the height, b is the base.
Answer:
a.323.03hrs,
b.No. Time not enough
Step-by-step explanation:
One team takes 
of the job per hour,
Team two takes 
of the job together.
#to get what times it takes the two to clean together, we find the LCM of their work rates:
#It takes the two13/4200 of the job per hour.
Combined work rate is thus 
Hence it takes the two teams 323.03hrs to clean the streets working together.
b.The crew team is set to begin in 1 week(7days). We therefore convert our time into days/weeks to verify viability;
Since one day equals 24hrs, the team will take
13.46days>7days
#NO, The time is not enough since 13.46days is higher than the 1week(7day) timeline.
Your answer is c 100 ÷ 5 = 20
The slope is 4/7
Y= 4/7x + 8/7
Hope this helped :)
To find the point of intersection, we want to set the two equations equal to each other to find where they meet. The problem is, we have two variables, which means we can't just set them equal to each other as is. We need to manipulate the equations so that we can remove one of the variables at a time to solve for the other one.
First, let's move y to one side so we can solve for x.
2x-3y=9
2x-9=3y
y=(2x-9)/3
5x+4y=11
4y=11-5x
y=(11-5x)/4
Now that they both equal the same thing (y), we can set them equal to each other and solve for x. This will give us the x value for the point of intersection of the lines.
(11-5x)/4=(2x-9)/3
3(11-5x)=4(2x-9)
33-15x=8x-36
33+36=8x+15x
69=23x
x=69/23
x=3
Now, we can do the opposite, and solve for x to find the y coordinate.
2x-3y=9
2x=3y+9
x=(3y+9)/2
5x+4y=11
5x=11-4y
x=(11-4y)/5
(3y+9)/2=(11-4y)/5
5(3y+9)=2(11-4y)
15y+45=22-8y
15y+8y=22-45
23y= -23
y= -1
The coordinates for the point of intersection of the two lines is (3, -1).
