Answer:
25/332
Step-by-step explanation:
let x = orginal price of the shorts
$21 = x(100%-20%) * 1.05
$21 = x(80%) * 1.05
$21 = 0.8x * 1.05
Subtract 1.05 from both sides
$19.95 = 0.8x
Divide 0.8 from both sides
$24.9375 = x
So the orginal price of the shorts are about $24.94
Answer:
12x6=42 sorry if im wrong
Step-by-step explanation:
Answer:
183.27miles
Step-by-step explanation:
Note that we are considering two planes.
Plane 1
Speed = 140 mph
Time = 2.5 hours
Distance = ?
Speed = distance/time
140 mph = distance/2.5hrs
Distance = 140×2.5
= 350miles
Plane 2
Speed = 170 mph
Time = 2.5 hours
Distance = ?
Speed = distance/time
170 mph = distance/2.5hrs
Distance = 170×2.5
= 425miles
The angle between side is 25 degree
From cosine rule
c^2 = a^2 + b^2 − 2abcos(tetha)
Where a = 350
b = 425miles
c^2 = 350^2+425^2-2(350×425)(cos25)
c^2 = 122500+180625-297500(0.906)
c^2 = 303125-269535
c^2 = 33590
C = √33590
C = 183.27miles
The distance they flew apart after 2.5hrs is 183.27miles
Answer: 37, 38, and 39
Step-by-step explanation: This problem states that the sum of 3 consecutive integers is 114 and it asks us to find the integers.
3 consecutive integers can be represented as followed.
X ⇒ <em>first integer</em>
X + 1 ⇒ <em>second integer</em>
X + 2 ⇒ <em>third integer</em>
<em />
Since the sum of our 3 consecutive integers is 114, we can set up an equation to represent this.
X + X + 1 + X + 2 = 114
We can simplify on the left side by combining the X's and the numbers.
3x + 3 = 114
-3 -3 ← <em>subtract 3 from both sides of the equation</em>
3x = 111
÷3 ÷3 ← <em>divide both sides of the equation by 3</em>
<em> </em>X = 37
X ⇒ <em>first integer = 37</em>
X + 1 ⇒ <em>second integer = 38</em>
X + 2 ⇒ <em>third integer = 39</em>
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<em>Therefore, our 3 consecutive integers are 37, 38, and 39.</em>
