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bearhunter [10]
3 years ago
9

A tower or mini tower pc is a type of all- in -one unit true or false

Computers and Technology
2 answers:
Evgen [1.6K]3 years ago
6 0
The answer is true it’s a type of all in one
Svetlanka [38]3 years ago
5 0

Answer:

thx

Explanation:

You might be interested in
How people select, interpret, remember, and use information to make judgments and decisions is called __________.
Svetradugi [14.3K]

Answer: Social Cognition

Explanation: hope this helps

6 0
3 years ago
What is the keyboard shortcut for opening the edit hyperlink dialog box
Mademuasel [1]

That would be CTRL+K


https://quizlet.com/122913134/keyboard-shortcuts-flash-cards/


hope this helps!

7 0
3 years ago
Write a Python function LetterGame() that repeatedly asks the user to input a letter. The function is to count the number of vow
kotegsom [21]

Answer:

def LetterGame():

   vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]

   count1 = count2 = 0

   while True:

       choice = input("Enter a letter / digit to stop: ")

       if choice.isdigit():

           break

       elif choice.isalpha():

           count1 += 1

           if choice in vowels:

               count2 += 1

   print("You entered " + str(count1) + " letters, " + str(count2) + " of which weere vowels.")

   print("The percentage of vowels was " + str(count2 / count1 * 100) + "%")

LetterGame()

Explanation:

Create a function called LetterGame

Inside the function:

Create a list of vowels

Initialize count1, counts the total letters, and count2, counts the vowels

Initialize a while loop that iterates until the specified condition is met in the loop

Get the input from the user. If it is a digit, stop the loop. If it is an alphabet, increase the count1 by 1, and also check if it is a vowel. If it is a vowel, increment the count2 by 1

When the loop is done, print the required information

Finally, call the function

4 0
3 years ago
1. Of Facebook, Twitter, and LinkedIn, which do you think is the best platform for marketing your personal brand? Explain.
lord [1]
Facebook cuz a lot more people on Facebook to see your personal brand
3 0
3 years ago
You are asked to simulate a binary search algorithm on an array of random values.An array is the list of similar type of element
Alex Ar [27]

Answer:

Explanation:

Problem statement:

to simulate a binary search algorithm on an array of random values.

Binary Search: Search a sorted array by repeatedly dividing the search interval in half. Begin with an interval covering the whole array. If the value of the search key is less than the item in the middle of the interval, narrow the interval to the lower half. Otherwise narrow it to the upper half. Repeatedly check until the value is found or the interval is empty.

Input/output description

Input:

Size of array: 4

Enter array:10  20 30 40

Enter element to be searched:40

The Output will look like this:

Element is present at index 3

Algorithm and Flowchart:

We basically ignore half of the elements just after one comparison.

Compare x with the middle element.

If x matches with middle element, we return the mid index.

Else If x is greater than the mid element, then x can only lie in right half subarray after the mid element. So we recur for right half.

Else (x is smaller) recur for the left half.

The Flowchart can be seen in the first attached image below:

Program listing:

// C++ program to implement recursive Binary Search

#include <bits/stdc++.h>

using namespace std;

// A recursive binary search function. It returns

// location of x in given array arr[l..r] is present,

// otherwise -1

int binarySearch(int arr[], int l, int r, int x)

{

   if (r >= l) {

       int mid = l + (r - l) / 2;

       // If the element is present at the middle

       // itself

       if (arr[mid] == x)

           return mid;

       // If element is smaller than mid, then

       // it can only be present in left subarray

       if (arr[mid] > x)

           return binarySearch(arr, l, mid - 1, x);

       // Else the element can only be present

       // in right subarray

       return binarySearch(arr, mid + 1, r, x);

   }

   // We reach here when element is not

   // present in array

   return -1;

}

int main(void)

{ int n,x;

cout<<"Size of array:\n";

cin >> n;

int arr[n];

cout<<"Enter array:\n";

for (int i = 0; i < n; ++i)

{ cin >> arr[i]; }

cout<<"Enter element to be searched:\n";

cin>>x;

int result = binarySearch(arr, 0, n - 1, x);

   (result == -1) ? cout << "Element is not present in array"

                  : cout << "Element is present at index " << result;

   return 0;

}

The Sample test run of the program can be seen in the second attached image below.

Time(sec) :

0

Memory(MB) :

3.3752604177856

The Output:

Size of array:4

Enter array:10  20 30 40

Enter element to be searched:40

Element is present at index 3

Conclusions:

Time Complexity:

The time complexity of Binary Search can be written as

T(n) = T(n/2) + c  

The above recurrence can be solved either using Recurrence T ree method or Master method. It falls in case II of Master Method and solution of the recurrence is Theta(Logn).

Auxiliary Space: O(1) in case of iterative implementation. In case of recursive implementation, O(Logn) recursion call stack space.

8 0
3 years ago
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