Hey there! :)
To find an equation of a line that passes through (5, 1) and has a slope of 2, we'll need to plug our known variables into the slope-intercept equation.
Slope-intercept equation : y = mx + b ; where m=slope, b=y-intercept
Since we're already given the slope, all we really need to do is find the y-intercept.
We can do this by plugging our known values into the slope-intercept equation.
y = mx + b
Since we're trying to find "b," we need to plug in "y, m, x" into our formula.
(1) = (2)(5) + b
Simplify.
1 = 10 + b
Subtract 10 from both sides.
1 - 10 = b
Simplify.
-9 = b
So, our y-intercept is 9!
Now, we can very simply plug our known values into slope-intercept form.
y = mx + b
y = 2x - 9 → final answer
~Hope I helped!~
Answer:
96
Step-by-step explanation:
Using side b as the base, 4 points makes 3 bases (the space in between). With three bases, you can have 3 bases of 1 segment, 2 bases of 2 segments, and 1 base of 3 segments. This equals 6 bases. Each of these can connect to a point on line a. 6x6=36
Using side a as the base, 6 points makes 5 bases. With 5 bases, you can have 5 bases of 1 segment, 4 bases of 2 segments, 3 bases of 3 segments, 2 bases of 4 segments, and 1 base of 5 segments. This equals 15 bases. Each of these can connect to a point on line b. 15x4=60
36+60=96
Wow the answer is b because you secelted it
Give me one sec to answer be back
