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atroni [7]
3 years ago
14

The screen on briannas new phone is 2.85 centimeters long. what mixed number represents the length of the phone screen?

Mathematics
1 answer:
hodyreva [135]3 years ago
6 0
Wait let me think this over

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I NEED HELP AS SOON AS POSSIBLE
Xelga [282]
The answer is D. 200m = 2cm. That's because to get from meters to centimeters, you need to multiply by 100. 200 * 100 is not 2, therefore D is the answer. 
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How do you write 76% as a fraction​
padilas [110]

Answer:

76/100 or simplified into 19/25

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Complete the sequence <br> 3, -6, 12, -24 , 48
scoundrel [369]

3*-2=-6

-6*-2=12

The sequence is a number being multiplied by -2 over and over.

48, -96, 192, -384, 768, etc.

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The rectangular prism has a volume of 936 cubic inches. Write and solve an equation to find the missing dimension of the prism.
nikdorinn [45]

Step-by-step explanation:

A rectangular prism is nothing but a cuboid. Let the length , width and height of the  rectangular prism be l, w and h.

We know that volume of a cuboid V = l×w×h

So,  l×w×h = 936

So, we can find any dimension of the prism provided the the other two dimensions are given to us.

4 0
3 years ago
Which of the following are roots of the following polynomial x^3-11x^2+33x+45
Mandarinka [93]
For x^3-11x^2+33x+45 , we can make it an equation so <span>x^3-11x^2+33x+45=0. Next, we can find out if -1 or -3 is a factor. If -1 is a factor, than (x+1) is factorable. Using synthetic division, we get 

      x^2-12x+45
       ___ ________________________
x+1 | x^3-11x^2+33x+45

      - (x^3+x^2)
       _________________________
            -12x^2+33x+45
          - (-12x^2-12x)
          ______________
            45x+45
         -(45x+45)
___________
0


Since that works, it's either B or D. We just have to figure out when
</span> x^2-12x+45 equals 0, since there are 3 roots and we already found one. Using the quadratic formula, we end up getting (12+-sqrt(144-180))/2=
(12+-sqrt (-36))/2. Since sqrt(-36) is 6i, and 6i/2=3i, it's pretty clear that B is our answer
8 0
3 years ago
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