Domain is the numbers you can use
range is the result of inputing the domain
an interesting fact is that the inverse of a function switches the domain and range
basically
the domain of f(x) becomes the range of f^-1(x)
the range of f(x) becomes the domain of f^-1(x)
so just find the domain and range of f(x)
there are no restrictions
all real numbers can be used
all real numbers can result
so the answer is domain and range for both is all real numbers
D is answer
Step-by-step explanation:
[1/2]^-2= 4
[1/3]^-2=9
[1/4]^-2=16
So sum is 4+9+16=29
Hope this helps you.
You would substitute the given value of “y” into the equation of -14x+y=16
-14x+5x-2=16
Then you would solve for “x”
x=2
You would then substitute the value of “x” into the equation to solve for “y”
y=5(2)-2
Which would then give you a value for “y”
y=12
So the answer is (2,12)
So,
Let x represent Joe's weight and y represent Jeff's weight.
"Joe weighs 20 lbs. less than twice Jeff's weight."
x = 2y - 20
"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
(y + 10) + x = 250
We now have our two open sentences.
x = 2y - 20
(y + 10) + x = 250
Get rid of parentheses.
x = 2y - 20
x + y + 10 = 250
We will use Elimination by Substitution.
2y - 20 + y + 10 = 250
Collect Like Terms.
3y - 10 = 250
Add 10 to both sides.
3y = 260
Divide both sides by 3.
Substitute again.
Multiply.
Subtract.
Check.
"Joe weighs 20 lbs. less than twice Jeff's weight."
Jeff's weight times two is 173 and one-third.
20 lbs. less than that is 153 and one-third lbs. Check.
"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
86 and two-thirds + 10 = 96 and two-thirds.
96 and two-thirds + 153 and one-third equals 250 lbs. Check.