Answer:
Part 22) The area is
and the perimeter is 
Part 24) The area is
and the perimeter is
Part 26) The area is equal to 
Step-by-step explanation:
Part 22) Find the perimeter and area
step 1
The area of a rectangle is equal to

we have


Remember that
When multiply exponents with the same base, adds the exponents and maintain the base
substitute in the formula


step 2
The perimeter of a rectangle is equal to

we have

substitute in the formula


Part 24) Find the perimeter and area
step 1
The area of triangle is equal to

where


Remember that
When multiply exponents with the same base, adds the exponents and maintain the base
substitute the given values


step 2
Find the perimeter
I will assume that is an equilateral triangle (has three equal length sides)
The perimeter of an equilateral triangle is

where

substitute


Part 26) Find the area
The area of a circle is equal to

where

Remember the property

substitute in the formula the given value


<u>Answer:</u>
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answer = CI = 3108 RUPEES
<u>Step-by-step explanation:</u>
i am doing the method in which u find the simple interest of first year then second year.
SI FOR 1ST YEAR= P X R X T / 100
SI = 2700 X 20 X 2 / 3 X 100 ( RATE OF INTEREST IS 20 / 3)
SI = 108000/300
SI = 360
SI FOR SECOND YEAR =
P = 2700 + 360= 3060
SI = 3060 X 20 X 2 / 300
SI= 122400 / 300
SI = 408
COMPOUND INTEREST (CI) = PRINCIPLE + SI OF 2ND YEAR
CI = 2700 + 408
CI = 3108 RUPEES
or u can solve be the method
CI = amount - principle
Amount= principle x (change in ratio) raised to time
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Answer:
IV/4
Step-by-step explanation:
Go to 15 on the x line and go down 12 and that’s the 4
Answer:
<u>x-intercept</u>
The point at which the curve <u>crosses the x-axis</u>, so when y = 0.
From inspection of the graph, the curve appears to cross the x-axis when x = -4, so the x-intercept is (-4, 0)
<u>y-intercept</u>
The point at which the curve <u>crosses the y-axis</u>, so when x = 0.
From inspection of the graph, the curve appears to cross the y-axis when y = -1, so the y-intercept is (0, -1)
<u>Asymptote</u>
A line which the curve gets <u>infinitely close</u> to, but <u>never touches</u>.
From inspection of the graph, the curve appears to get infinitely close to but never touches the vertical line at x = -5, so the vertical asymptote is x = -5
(Please note: we cannot be sure that there is a horizontal asymptote at y = -2 without knowing the equation of the graph, or seeing a larger portion of the graph).