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Greeley [361]
3 years ago
9

Simplify the expression. 9y^2−25/9y^2−30y+25

Mathematics
1 answer:
mezya [45]3 years ago
4 0

Answer:

Step-by-step explanation:

56y^2/9-30y+25

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How does the graph of y=3x-4 compare to the graph of y=3x+2
serious [3.7K]
One is negative 4 and one is positive 2
3 0
3 years ago
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Which ordered pair is generated from the equation shown below? y = 3x - 1 A. (6, 18) B. (6, 17) C. (4, 12) D. (9, 8)
geniusboy [140]

Answer:

B 6,17

Step-by-step explanation: If you plug in the value of x from each of the choices only b gives the correct value of y. If you put 6 in the place of x in y= 3x-1    then y= 18-1 which is 17, and it does say 17 in 6,17.

7 0
3 years ago
Directions for questions 4 & 5: We selected a random sample of 100 StatCrunchU students, 67 females and 33 males, and analyz
GaryK [48]

Answer:

The 95% confidence interval for the difference between means is (-2164.21, -299.13).

The lower limit on the confidence interval is -$2164.21.

The upper limit on the confidence interval is -$299.13.

Step-by-step explanation:

The sample data is:

Gender   Mean          Std. dev.     n

Female    2577.75      1916.29     67

Male        3809.42     2379.47     33

We have to calculate a 95% confidence interval for the difference between means, with a T-model.

The sample 1, of size n1=67 has a mean of 2577.75 and a standard deviation of 1916.29.

The sample 2, of size n2=33 has a mean of 3809.42 and a standard deviation of 2379.47.

The difference between sample means is Md=-1231.67.

M_d=M_1-M_2=2577.75-3809.42=-1231.67

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{1916.29^2}{67}+\dfrac{2379.47^2}{33}}\\\\\\s_{M_d}=\sqrt{54808.468+171572.045}=\sqrt{226380.513}=475.795

The t-value for a 95% confidence interval is t=1.96.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=1.96 \cdot 475.795=932.54

Then, the lower and upper bounds of the confidence interval are:

LL=M_d-t \cdot s_{M_d} = -1231.67-932.54=-2164.21\\\\UL=M_d+t \cdot s_{M_d} = -1231.67+932.54=-299.13

The 95% confidence interval for the difference between means is (-2164.21, -299.13).

6 0
3 years ago
Find the output, y, when the input, x , is 7.<br> y=
Anton [14]
The answer to your question would be 6!
4 0
3 years ago
What is the missing number ?? /6 =25/30
matrenka [14]

Answer:

5

Step-by-step explanation:

\frac{25}{30} ( divide numerator and denominator by 5 ) , then

\frac{25}{30} = \frac{5}{6} ( with missing number ? = 5 )

8 0
2 years ago
Read 2 more answers
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