You need to multiply those three numbers (7x9)x6=378.
Answer:
2,840
Step-by-step explanation:
since the three is in the tens place and 7 in single <em>if 5 and up round up fi 4 and below leave it alone you</em> will then take the 3 and round up to give you 2,840
Answer:
Option D.
Step-by-step explanation:
We have the inequality:
3 + (5/2)*x ≥ 2*x - 13/2
First, let's try to isolate x in one side of the inequality:
3 + (5/2)*x ≥ 2*x - 13/2
(5/2)*x ≥ 2*x - 13/2 - 3
(5/2)*x - 2*x ≥ - 13/2 - 3
Now all the terms with an x are in the left, and the terms without are in the right.
We can rewrite this inequality as:
(5/2)*x - (4/2)*x ≥ - 13/2 - 6/2
(1/2)*x ≥ -19/2
Now, multiplying both sides by 2 we get:
2*(1/2)*x ≥ (-19/2)*2
x ≥ - 19
So the graph will be a solid point in x = -19, and a ray that extends to the right (the values that are larger than -19)
The correct option is the last graph, option D.
Answer: options b and c
<u>Step-by-step explanation:</u>
∠ACD is supplementary to ∠ACE <em>given</em>
∠ACD is supplementary to ∠BCD <em>given</em>
⇒ ∠ACE is supplementary to ∠BCD <em>transitive property</em>
∠ACD ≅ ∠BCE <em>given</em>
⇒ ∠BCE is supplementary to ∠ACE <em>substitution</em>
and ∠BCE is supplementary to ∠BCD <em>substitution</em>
********************************************************************************
multiple choice options:
a) ∠ACE is supplementary to ∠BCD <em>False</em>
b) ∠BCE is supplementary to ∠ACE <em>TRUE</em>
c) ∠BCD is supplementary to ∠BCE <em>TRUE</em>
d) ∠ACE ≅ ∠BCE <em> False</em>
e) ∠BCD ≅ ∠ACE <em>False</em>
Answer:
25π
Step-by-step explanation:
1) for whole circuit: A=π*r², where r - radius of the given circle;
2) for a quater of the circuit: A=πr²/4;
3) finally, A=π*100/4=25π.
