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s2008m [1.1K]
3 years ago
10

[ Easy Math ] Help me pls

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
7 0

Answer:

1) you're going to have to flip the coins (or fake numbers) for the experimental trials.

2) for the theoretical, there is 1/2 chance for heads or tails with each toss, so you'd expect that out of 10 tosses, 5 heads, 5 tails. out of 100 tosses- 50 heads, 50 tails.

When tossing 2 coins- 1/2×1/2 = 1/4 (25%) chance that 2 heads, 2 tails, or 1 heads & 1 tails. Deviation value comes from after you done your flipping and recorded your data. So if on 100 flips you actually got 50 and 50 (rarely us that exact ;), the deviation from the expected of 50/50 would be 0.00. If however you flipped 100 heads or 100 tails (impossible), then the deviation value would be 1.00.

|(100-50)| ÷ 50 = 50÷50 = 1.00

So usually you may have data like: 47/53 or something a little off than 50/50, making deviation |(47-50)| ÷ 50 = 3÷50 = 0.06.

Now the number of flips is important for the outcome! So if a coin toss if 10 times had 4 heads, 6 tails, the deviation value would be:

|(4-5)| ÷ 5 = 1÷5 = 0.20

So increasing the # flips DECREASES the deviation value!!

Whether it's from 10 to 100, or from 100 to 200. Look at my example of how the 10-flip deviation of 0.20 decreased to 0.06 with 100-flip

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Plz help me out with this
nadya68 [22]

Given,

  • HK is the perpendicular bisector of GJ. So, <u>GK = KJ</u>.
  • GK = 2x + 10
  • KJ = 3x - 15

_______________

Find KJ .

_______________

First find the value of x

\sf \: GK \:  = KJ \\\sf 2x + 10 = 3x - 15 \\\sf 2x - 3x =  - 15 - 10 \\ \sf - x =  - 25 \\  \sf \: -  >   \boxed{\bf \: x = 25}

Now, find the value of KJ.

\sf3x - 15 \\  \sf= 3(25) - 15 \\  \sf=7 5 - 15 \\     = \boxed{\bf \: 60}

-> The value of KJ is <u>6</u><u>0</u><u>.</u>

_______________

Hope it helps.

RainbowSalt2222

6 0
3 years ago
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erik [133]
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3 years ago
The three medals earned in the Olympics are the gold, silver, and bronze medals. In the 2014 Winter Olympics, the United States
marta [7]

Answer:

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We also know that the number of bronze medals was 4 less than the sum of gold and silver, so if there are x + 2 of gold and x of silver, there are x+x+2-4 of bronze.

Now, we can do an equation, as we know there were a total of 28 medals:

x + x + 2 + x + x + 2 - 4 = 28

And we isolate x:

4x = 28

x = 28/4 = 7

There were 7 silver medals, so there were 9 gold ones (7-2) and 12 of bronze (9+7-4).

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Jeanette's salary is 25000 a year she gets a 4% raise annually, how much will she have after 7 years
Mars2501 [29]
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8 0
3 years ago
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2(4 t) written in distributive property
ss7ja [257]
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