The answer to that is a Pixel
I think so that it will be zero or more
Lowercase a is decimal 97 ; upper case is decimal 65
It's easier to think of them in octal, however: a = octal 141, and A is octal 101
octal to binary is easy, each digit is three bits.
141 = 001 100 001
101 = 001 000 001
So, how many bits are changed above?
Answer:
(d) if (radius > 0) System.out.println(radius * radius * 3.14159);
Explanation:
Given
Code segment (a) to (d)
Required
Which is correct
Code segment (a): radius <=0
This means that radius is 0 or less, i.e. 0 or negative
Code segment (b): radius !=0
This means that radius is not equal to 0 i.e. it could be positive or negative but definitely not 0
Code segment (c): radius >=0
This means that radius is 0 or greater, i.e. 0 or positive
Code segment (d): radius >0
This means that radius is greater than 0 i.e. positive
<em>Hence, (d) is correct</em>
