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MA_775_DIABLO [31]
3 years ago
9

If f(x)=5x^2 and g(x)=x-2 what is (fog)(-3)

Mathematics
1 answer:
olga2289 [7]3 years ago
7 0

Answer:

(fog)(-3) = 125

Step-by-step explanation:

So, we need to first evaluate g(-3) and then plug the value of g(-3) into f(x) to find (fog)(-3). So, let's do that:

g(-3) = -3-2 = -5

f(g(-3)) = f(-5) = 5(-5)^2 = 5(25) = 125

Thus, (fog)(-3) = 125.

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2 years ago
1. The position of a particle moving along a coordinate axis is given by: s(t) = t^2 - 5t + 1. a) Find the speed of the particle
zimovet [89]

Answer: \left |  2t-5\right |,\ 2,\ 2t-5

Step-by-step explanation:

Given

Position of the particle moving along the coordinate axis is given by

s(t)=t^2-5t+1

Speed of the particle is given by

\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=\left |  2t-5\right |

Acceleration of the particle is

\Rightarrow a=\dfrac{dv}{dt}\\\\\Rightarrow a=2

velocity can be negative, but speed cannot

\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=2t-5

3 0
3 years ago
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Nadya [2.5K]

Answer:

t:

\infty , -  \infty

meaning any number can substitute t and it would be the same answer.

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