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katrin2010 [14]
3 years ago
7

Does anyone know I need help on this?!!

Mathematics
1 answer:
Pavel [41]3 years ago
8 0

Answer:

A. yes B. no C. no D. yes

Step-by-step explanation:

ur welcome luv

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A certain drug dosage calls for 17 mg per kg per day and is divided into two doses (1 every 12 hours). If a person weighs 255 po
vekshin1

Answer:

985.15mg

Step-by-step explanation:

Calculation for how many milligrams of the drug should he receive every 12 hours

First step is to calculate the weight in kg

255 lbs = 255/2.2 = 115.9 kg

Second step is multiply mg/kg in order to get total medicine per day

Dose per day=115.9kg × 17 mg

Dose per day= 1,970.3

Third step is to calculate how many milligrams of the drug should he receive by dividing the day dose by 2

Dose milligrams=1,970.3/2

Dose milligrams=985.15mg

Therefore how many milligrams of the drug should he receive every 12 hours will be 985.15mg

3 0
3 years ago
What is equivalent to <br> (3x+1)(4x-1)
valentinak56 [21]
(3x+1)(4x-1)

3x+4x=7x
1-1=0

So

(3x+1)(4x-1) = 7x

I hope this helped and was right, have a nice day
4 0
2 years ago
A stone is dropped from the top of a tower. The height h in meters from where the stone is dropped to the ground is given by the
CaHeK987 [17]

Wag umasa sa brainly

Step-by-step explanation:

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5 0
2 years ago
Can some one pls help
Olegator [25]

Answer:

Draw an open circle on 3 and shade to the left.

Step-by-step explanation:

First, solve the inequality.

x - 6 < -3

x - 6 + 6 < -3 + 6

x < 3

The less than symbol (<) indicates that 3 is not part of the solution set. Therefore, the circle will be open.

Since the inequality indicates that x is less than 3, shade to the left of 3.

Hope that helps. :)

3 0
3 years ago
It costs Sally 20 cents to make a cup of lemonade, and she sells each cup for 50 cents. She is using the following identity to c
mote1985 [20]

She would make 3.00 dollars


50(10) - 20(10) = (10)(50 - 20)

500 - 200 = (10 * 30)

300 = 300


(10)(50 - 20) = 30(10)

(10 * 30) = 300

300 = 300

3 0
3 years ago
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