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murzikaleks [220]
3 years ago
15

Use a graphing calculator to graph the function below. What is the

Mathematics
1 answer:
snow_tiger [21]3 years ago
5 0

Answer:

-3

Step-by-step explanation:

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Write the equation in standard form.<br><br> 8−5y=−2x
MrMuchimi

bearing in mind that

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient


8 - 5y = - 2x

2x - 5y = - 8

4 0
3 years ago
On a recent trip, Juan started at an elevation of 1200 feet above sea level. He descended into a valley 20.4 feet below sea leve
liraira [26]

A would be the correct answer because he is up in elevation so that makes the 1200 positive and he goes down 20.4 which is negative and is goes that far down!!

hope this helps

3 0
3 years ago
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A candy store makes strawberry cream chocolates every 8 days and white chocolate truffles every 12 days. The candy store made bo
Elanso [62]

Answer:

on the 24th day they both will make chocolate the LCM of 8 and 12 is 24

4 0
3 years ago
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What's the mean median and mode of 8,2,3,5,7​
Alex_Xolod [135]

Answer:

mean:25     median:3        there is no mode

Step-by-step explanation:

4 0
3 years ago
Andrea was watching her brother in the ocean and noticed that the waves were coming into the beach at a frequency of 0.367347 Hz
anygoal [31]

Answer:

<u>18 waves</u> hit the beach in 49 s.

Step-by-step explanation:

Given:

The frequency of the waves that were coming into the beach is 0.367347 Hz.

Now, to find the number of waves that hit the beach in 49 s.

Let the number of waves be n.

The frequency of waves (f) = 0.367347 Hz.

The time it takes to hit the beach (t) = 49 s.

Now, we put formula to get the number of waves:

f=\frac{n}{t} \\\\0.367347=\frac{n}{49} \\\\Multiplying\ both\ sides\ by\ 49\ we\ get:\\\\18.000003=n\\\\n=18.000003.

<u><em>The number of waves = 18.</em></u>

Therefore, 18 waves hit the beach in 49 s.

8 0
3 years ago
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