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11Alexandr11 [23.1K]
2 years ago
7

I’m stuck and I would really like your help.

Mathematics
2 answers:
Alekssandra [29.7K]2 years ago
8 0

Answer:

x= 12

Step-by-step explanation:

2x-20=40-3x  multiply both sides of the equation by 5

2x+3x= 40+20 move the terms

5x= 40+20 collect like terms

5x = 60 add the numbers

5x= 60 divide both sides by 5

x=12

Neporo4naja [7]2 years ago
6 0

Answer:

Answer: 1/12

Step-by-step explanation:

2/5x-4=8-3/5x.

We want to tank x out of the denominator by multiplying x on both sides.

2/5-4x=8x-3/5

Now we simplify

-12x=-1

x=1/12

Put x in the equation to check it

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3 years ago
Can u solve this problem in show your work
aksik [14]

Hey there!

We can solve this problem by doing PEMDAS, which lists:

Parentheses \\ Exponents \\ Multiplication \\  Division \\ Addition \\ Subtraction

We have in this equation

Parentheses \\ Exponents \\ Dvision

Let's sp;ve this equation now!

Parentheses ↓

(6 -3) = 3

Exponents ↓

3^2  = 9

Division ↓

\frac{36}{9}  = 9

Okay now , I show you the steps so it can be easier to solve!

\frac{36}{(6-3)^2} \\ \\  6-3 = 3 \\   \\ \frac{36}{3^2}  \\ \\ 3^2 = 9   \\  \\ \frac{36}{9} \\ \\ \\ \\ Answer: 4

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

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Step-by-step explanation:

The given equation is 4x^{2}-8x-1

Let a be the coefficient of x^{2}

Let b be the coefficient of x

Let c be the constant.

Then the roots α,β for the equation ax^{2}+bx+c are \dfrac{-b+\sqrt{b^{2}-4ac} }{2a},\dfrac{-b-\sqrt{b^{2}-4ac} }{2a}

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β=\frac{-b-\sqrt{b^{2}-4ac} }{2a}=\frac{8-\sqrt{64+16} }{8}=\frac{8-4\sqrt{5}}{8}=1-\frac{\sqrt{5}}{2}.

So the roots are 1+\frac{\sqrt{5}}{2},1+\frac{\sqrt{5}}{2}

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