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Talja [164]
2 years ago
8

(5x + 10) + (2x -3) =

Mathematics
2 answers:
vladimir1956 [14]2 years ago
7 0

Answer: 7x+7

Step-by-step explanation:1

Eliminate redundant parentheses

(5x+10)+(2x-3)

(5x+10)+(2x−3)

5x+10+2x-3

5x+10+2x−3

2

Subtract the numbers

5x+10+2x−3

5x+7+2x

Combine like terms

5x+7+2x

 

7x+7

Solution

7x+7

Black_prince [1.1K]2 years ago
6 0

Answer:

16

Step-by-step explanation:

I think sorry if I'm wrong

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The equation 3x - 2y = 8 and 6x - 4y = 16 are systems of equations with infinite solutions.

A linear system of equations can have (a)unique solutions, (b) infinite number of solutions, or (c) no solution.

For it to have infinite number of solutions, the graph of the equations must intercept with each other at infinite points, leaving the two graphs overlaying each other.

Given the equation, 3x - 2y = 8, the other equation in a linear system to have infinite number of solutions with it must be the exact same line.

To do this, simply multiply the whole equation with a real number.

Example:

Multiplying the whole equation by 2 gives 6x - 4y = 16.

Now, 3x - 2y = 8 and 6x - 4y = 16 are equations in a linear system with infinite number of solutions.

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1 year ago
Vector V is in standard position and makes an angle of 50° with the positive x-axis. Its magnitude is 18. Write V in component f
Umnica [9.8K]

Answer:

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11.57i + 13.79j

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b = 18sin50° = 13.79 units upwards

check if your answer is correct

\sqrt{11.57^{2} +13.79^{2} } = 18.0

In vector component form ai + bj = 11.57i + 13.79j

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3 years ago
Help FAST PLZ!!! marking brainliest!
ss7ja [257]

Answer:

After finding the prime factorization of $2010=2\cdot3\cdot5\cdot67$, divide $5300$ by $67$ and add $5300$ divided by $67^2$ in order to find the total number of multiples of $67$ between $2$ and $5300$. $\lfloor\frac{5300}{67}\rfloor+\lfloor\frac{5300}{67^2}\rfloor=80$ Since $71$,$73$, and $79$ are prime numbers greater than $67$ and less than or equal to $80$, subtract $3$ from $80$ to get the answer $80-3=\boxed{77}\Rightarrow\boxed{D}$.

Step-by-step explanation:

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