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Veseljchak [2.6K]
3 years ago
12

If one wheel on bob model is 4 inches across how many inches is the actual wheel on the bike

Mathematics
1 answer:
Alik [6]3 years ago
8 0

Answer:

16 inches


Step-by-step explanation:


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5. Michael is going to buy a new pair of shoes. The shoes cost $44.20. He has to pay 15% tax on the
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Answer:

$50.83

Step-by-step explanation:

44.20 x .15 = 6.63

44.20 + 6.63= 50.83

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5. C. Liquid 2 because 3ml = 1g, 6ml = 2g

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What is the mean, median, and mode of 6,2,3,4,4,2,8,5,2​
bearhunter [10]

Answer:

Mode=2

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Step-by-step explanation:

Mode you add all the numbers and divide by the actual number of the numbers given.

Median you cancel the numbers from first to last until you reach the one in the middle that's going to be the median.

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3 years ago
Suppose a batch of metal shafts produced in a manufacturing company have a standard deviation of 1.5 and a mean diameter of 205
Crank

Answer:

P(205-0.3=204.7

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

Step-by-step explanation:

Let X the random variable that represent the diamters of interest for this case, and for this case we know the following info

Where \mu=205 and \sigma=1.5

We can begin finding this probability this probability

P(205-0.3=204.7

For this case they select a sample of n=79>30, so then we have enough evidence to use the central limit theorem and the distirbution for the sample mean can be approximated with:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}

And we can find the z scores for each limit and we got:

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

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3 years ago
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