The point P(–4, 4) that is 
of the way from A to B on the directed line segment AB.
Solution:
The points of the line segment are A(–8, –2) and B(6, 19).
P is the point that bisect the line segment in .
So, m = 2 and n = 5.
By section formula:
P(x, y) = (–4, 4)
Hence the point P(–4, 4) that is of the way from A to B on the directed line segment AB.
Answer:
y= 1/3 x +5
Step-by-step explanation:
To find the slope, we take two points
(0,5) and (15,10)
The slope is found by the formula
m = (y2-y1)/ (x2-x1)
= (10-5)/(15-0)
= 5/15
= 1/3
The slope is 1/3
The y intercept is found when x=0
When x=0 y=5
The slope intercept form of the line is
y=mx+b where m is the slope and b is the y intercept
y= 1/3 x +5
Part a), solve this system of equations:
x + y = 5
x - y = 2.25
2x = 7.25
x = 3.625
y = 1.375
part b), solve this system of equations:
x + y = 5
x = 3y
y = 1.25
x = 3.75
Answer:
All of them are parallel
Step-by-step explanation:
This is due to the all of the 90 degree angle which would make the rest of the line a would be another 90 degree angle Which are found on every line. This would make all of the lines parallel because it is a total of 180 degrees.
