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maxonik [38]
2 years ago
10

According to Newton's Second Law of Motion, the force acting on an object varies directly with the object's acceleration. Suppos

e that a force of 56 N results in an acceleration of 8 /ms2 . If the force is changed to 35 N , what will the object's acceleration become?
Mathematics
1 answer:
Marta_Voda [28]2 years ago
5 0
Repost this in science. this is physics not math. physics is science.
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-2a-10+a=-28 please help me
Svetradugi [14.3K]

Answer:

a=18

Step-by-step explanation:

-2a-10+a=-28

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Suppose you cool a pot of soup in a 20°C room. Right when you take the soup off the stove, you measure its temperature to be 180
dezoksy [38]

Answer:

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  • 53.6°C

Step-by-step explanation:

The temperature of the soup is described by Newton's Law of Cooling, which says the rate of change of temperature is proportional to the difference between the temperatures of the soup and the room. The solution to this differential equation is the exponential function ...

  f(t) = a +b·c^(t/τ)

where a is the room temperature, b is the initial difference in temperature, and c is the fractional change in the difference in temperature over time period τ.

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<h3>application</h3>

For the given scenario, we find ...

  a = room temperature = 20 . . . . degrees C

  b = (180 -20) = 160 . . . . degrees C

  c = (100 -20)/(180 -20) = 80/160 = 1/2 . . . . in τ = 20 minutes

So, the formula for the temperature of the soup is ...

  f(t) = 20 +160(1/2)^(t/20) . . . . . . . degrees C after t minutes

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<h3>time to 80°C</h3>

Solving for t when f(t) = 80, we find ...

  80 = 20 +160(1/2)^(t/20)

  3/8 = (1/2)^(t/20) . . . . . subtract 20, divide by 160

  20×log(3/8)/log(1/2) = t ≈ 28.3 . . . take logarithms, divide by coefficient of t

It will take about 28.3 minutes to cool to 80°C.

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<h3>temp at 45 minutes</h3>

The temperature after 45 minutes is ...

  f(45) = 20 +160(1/2)^(45/20)

  f(45) ≈ 53.6 . . . . degrees C

After 45 minutes the temperature of the soup will be about 53.6°C.

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1 year ago
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Step-by-step explanation:

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Figure ABCD is a parallelogram.
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